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2 years ago

How did the uncertainty principle influence thinking about the arrangement of electrons in atoms?

Chemistry

1 answer:

pishuonlain [190]2 years ago

3 0

Answer:

The correct answer is option C

Explanation:

According to Heisenberg's principle "At the instant of time when the position is determined, that is, at the instant when the photon is scattered by the electron, the electron undergoes a discontinuous change in momentum. This change is the greater the smaller the wavelength of the light employed, i.e., the more exact the determination of the position. At the instant at which the position of the electron is known, its momentum therefore can be known only up to magnitudes which correspond to that discontinuous change; thus, the more precisely the position is determined, the less precisely the momentum is known".

Hence, this principle made scientists to realize that electrons could not be located in defined orbits which a contradictory of Bohr's model.

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Explain and describe how the photoelectric effect occurs on an atomic level in terms of protons, neutrons, and electrons

grin007 [14]

Answer:

The photoelectric effect is the emission of electrons when electromagnetic radiation, such as light, hits a material. Electrons emitted in this manner are called photoelectrons.

Based on the wave model of light, physicists predicted that increasing light amplitude would increase the kinetic energy of emitted photoelectrons, while increasing the frequency would increase measured current.

3 0

2 years ago

In a compound, such as CH3OH, how determine which is the central atom?

svetlana [45]

Answer:

Choose the least electronegative atom other than H.

Explanation:

A Lewis structure consists of terminal atoms and one or more central atoms.

H can be only a terminal atom because it can form only one bond.

So the central atom must be either C or O.

The central atom is the less electronegative atom: C.

So, start the Lewis structure with a central C atom.

Then attach an O atom to get C-O.

Finally, attach the H atoms.

The condensed formula often gives you a clue where they go.

The formula CH₃OH implies that there are 3 H atoms on C and one on O.

The connectivity of the atoms is then as in the diagram below.

3 0

2 years ago

Normally the capital ÎGoÂ° for a reaction would be determined at standard temperature with each reactant at a concentration of 1

Arte-miy333 [17]

Answer:

d.-379 cal/mol

Explanation:

ΔG = ΔG⁰ + RT ln K

for equilibrium ΔG = 0

ΔG⁰ + RT ln K =0

ΔG⁰ = - RT ln K

PG ⇒ PEP

K = [ PEP ] / [ PG ]

= .68 / .32

= 2.125

ΔG⁰ = - 1.987 x 273 x ln 2.125

= - 409 Cal / mole

Option d is the nearest answer .

8 0

3 years ago

How many liters of carbon dioxide can be produced if 37.8 grams of carbon disulfide react with excess oxygen gas at 28.85 degree

alekssr [168]

37.8 grams of CS2 equals to 37.8/76=0.5 mole. So the products have 0.5 mole CO2 which is 11.2 liters at STP. So according to the gas law, the volume at given condition is 12.4 liters. So the answer should be 12.2 liters.

8 0

2 years ago

Determine the mass of Al(C2H3O2)3 that contains 2.63 Χ 1024 atoms of oxygen.

sergejj [24]

The molecular formula of compound is $Al(C_{2}H_{3}O_{2})_{3}$ .

Since, in 1 mole of $Al(C_{2}H_{3}O_{2})_{3}$ there are $6.023\times 10^{23}$ atoms of $Al(C_{2}H_{3}O_{2})_{3}$ .

Thus, according to molecular formula, in 1 mole of $Al(C_{2}H_{3}O_{2})_{3}$ there are $6\times 6.023\times 10^{23}=3.61\times 10^{24}$ atoms of oxygen atoms.

1 atom of oxygen will be present in $\frac{1}{3.61\times 10^{24}}$ moles of $Al(C_{2}H_{3}O_{2})_{3}$ . Thus,

$2.63\times 10^{24} atoms of oxygen \rightarrow \frac{2.63\times 10^{23}}{3.61\times 10^{24}}= 0.7285 moles of Al(C_{2}H_{3}O_{2})_{3}$ .

Molar mass of $Al(C_{2}H_{3}O_{2})_{3}$ is 236 g/mol, mass can be calculated as follows:

$m=n\times M=0.7285 mol\times 236 g/mol=172 g$

Therefore, mass of $Al(C_{2}H_{3}O_{2})_{3}$ will be 172 g.

5 0

3 years ago

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