Answer:
40.7062 °C
Explanation:
Let the initial temperature = x °C
Boiling temperature of water = 100 °C
Using,
Q = m C ×ΔT
Where,
Q is the heat absorbed in the temperature change from x °C to 100 °C.
C gas is the specific heat of the water = 4.184 J/g °C
m is the mass of water
ΔT = (100 - x) °C
Given,
Mass = 2350 g
Q = 5.83 × 10⁵ J
Applying the values as:
Q = m C ×ΔT
5.83 × 10⁵ = 2350 × 4.184 × (100 - x)
<u>x, Initial temperature = 40.7062 °C </u>
To find average atomic mass you multiply the mass of each isotope by its percentage, and then add the values up.
35 * 0.90 + 37 * 0.08 + 38 * 0.02 = 35.22
Average atomic mass closest to 35.22 amu.
The reactant is what you begin with.
The product is what you end up with (so the answer is B)
