Answer:
The boiling point of NaBr is higher than that of Na2S
Explanation:
Bromine has higher electronegativity as compared to the sulphur. The ionic strength of the bond formed with Sodium is higher in the NaBr compound. The higher the ionic bond strength the higher will be the boiling point
Also the size of bromine is large as compared to that of sulphur. Large molecules consists of more electron and hence they create der Waals attractive forces due to which the boiling point of compound increases.
Hence, the boiling point of NaBr is higher than that of Na2S
Answer:
70.88 mL volume of 1.27 M of HCl is required.
Explanation:
Given data:
Initial volume = ?
Initial molarity = 1.27 M
Final volume = 197.4 mL
Final molarity = 0.456 M
Solution:
Formula:
M₁V₁ = M₂V₂
Now we will put the values in formula.
1.27 M × V₁ = 0.456 M × 197.4 mL
V₁ = 0.456 M × 197.4 mL/1.27 M
V₁ = 90.014M.mL/1.27 M
V₁ = 70.88 mL
70.88 mL volume of 1.27 M of HCl is required.
Answer:
Reasonable Second step- 
Explanation:
The given single step chemical reaction is as follows.
Suppose a two-step mechanism is proposed for this reaction,
The reaction occured in two steps they are as follows.
Answer:
Evaporation wll occur
Explanation:
Boiling point is reached when the vapor pressure equals the atmospheric pressure around. The vapor pressure is the pressure exerted by a gas which is in contact with its own solution or liquid. It increases with increasing temperature.
The atmospheric pressure is the pressure of the atmosphere around. When the vapor pressure exceeds atmospheric pressure, boiling point is reached and surpassed. At this point, evaporation will occur.
It can be related to an egg drop because the forces pushing the egg up and down must follow the law
