Ask question

Ask question

All categories

3 years ago

5

CH3CH2OH______ionsin an aqueous solution.АformsBdoes not form

1 answer:

Leokris [45]3 years ago

3 0

Answer:

When ionic compounds dissolve, they break apart into ions which are then able to conduct a current ( conductivity ). ... Many molecular compounds, such as sugar or ethanol, are nonelectrolytes. When these compounds dissolve in water, they do not produce ions.

Explanation:

You might be interested in

What type of bonding holds the atoms in an h2o molecule together?

Ivanshal [37]

Covalent bond two non metals

3 0

3 years ago

Xavier was conducting a long term study of two populations of butterflies. Both populations had the same number of individuals.

nata0808 [166]

B. I had that same question!!

8 0

3 years ago

A sample of a substance containing only magnesium and chlorine was tested in the lab and was found to be composed of 74.5% chlor

chubhunter [2.5K]

Use a ratio to find out that x/190.2 = 74.5/100

hope this helps

8 0

3 years ago

Which pair of ions can form an ionic bond with each other and why? A.Cu and Ag; They are both metal ions.B. S and O; They have l

kap26 [50]

Opposite pairs form ionic bonds, due to this the answer is D - Li and Br; They have unlike charges.

5 0

4 years ago

Read 2 more answers

Acetylsalicylic acid (aspirin), HC9H7O4, is the most widely used pain reliever and fever reducer. Find the pH of 0.035 M aqueous

KatRina [158]

<u> </u> The pH of 0.035 M aqueous aspirin is 2.48

<u>Explanation:</u>

We are given:

Concentration of aspirin = 0.035 M

The chemical equation for the dissociation of aspirin (acetylsalicylic acid) follows:

$HC_9H_7O_4\rightleftharpoons H^++C_9H_7O_4^-$

<u>Initial:</u> 0.035

<u>At eqllm:</u> 0.035-x x x

The expression of $K_a$ for above equation follows:

$K_a=\frac{[C_9H_7O_4^-][H^+]}{[HC_9H_7O_4]}$

We are given:

$K_a=3.6\times 10^{-4}$

Putting values in above expression, we get:

$3.6\times 10^{-4}=\frac{x\times x}{(0.035-x)}\\\\x=-0.0037,0.0033$

Neglecting the value of x = -0.0037 because concentration cannot be negative

So, concentration of $H^+$ = x = 0.0033 M

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

$H^+$ = 0.0033 M

Putting values in above equation, we get:

$pH=-\log(0.0033)\\\\pH=2.48$

Hence, the pH of 0.035 M aqueous aspirin is 2.48

7 0

3 years ago