Answer:
please the answer below
Explanation:
(a) If we assume that our origin of coordinates is at the position of charge q1, we have that the potential in both points is
k=8.89*10^9
For both cases we have
(b) by replacing this values of r in the expression for V we obtain
hope this helps!!
Answer:
B. When the ball is released, the thrower's arm transfers its energy to the ball.
Answer:
fr = 514.5 N, This force has the opposite direction to the applied force.
Explanation:
Let's propose the solution of the problem using Newton's Second Law, we place a reference frame with the horizontal x-axis
Y axis
N- W = 0
N = W
X axis
F -fr = m a
the friction force has the expression
fr = μ N
fr = μ mg
fr = 0.35 150 9.8
fr = 514.5 N
This force has the opposite direction to the applied force.
The student's answer is incorrect because the friction coefficient must be multiplied by the normal
<span>This problem asks that we compute the magnitude
of the maximum stress that exists at the tip of an internal crack
</span> sigmam=2*(sigma0)(a/(pt))^(1/2)
sigmam= 2*(180)*(((3.5×10^-2)/(2))/(4.5×10-4))^(1/2)=2245 MPA (325609.7 PSI)
Answer:
The acceleration is
Explanation:
From the question we are told that
The mass of the engine is
The mass of each Boxcar is
The tension between the locomotive and boxcar A is
Generally the tension between the locomotive and boxcar A is equivalent to the net force propelling the box cars so the tension is mathematically represented as
Here M is the mass of the three box cars
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