All categories

3 years ago

if a car is moving down the highway at a constant velocity what does this mean about the cars acceleration?

Physics

1 answer:

Soloha48 [4]3 years ago

8 0

If a car is moving with constant speed that means rate of change of speed is zero. Hence, acceleration is zero.

You might be interested in

If you double the net force on an object what is the result on the acceleration?

melamori03 [73]

Answer:the acceleration will double

Explanation:

3 0

3 years ago

Importance of electrical symbol

Vsevolod [243]

The electrical symbols are very important especially when fixing electrical appliances because it tells you where the wire of neutral and live go.

8 0

3 years ago

Two identical 9.10-g metal spheres (small enough to be treated as particles) are hung from separate 300-mm strings attached to t

Musya8 [376]

Answer:

$n = 1.266\times 10^{12}$

Explanation:

Given data:

mass of sphere is 10 g

Angle between string and vertical axis is $\theta = 13 degree$

thickness of string 300 mm = 0.3 m

$sin\theta =\frac{2}{0.3 m}$

r =0.3 sin 13 = 0.067 m

$Fe = \frac{ kq_1 q-2}{d^2}$

$Fe = \frac{kq^2}{(2r)^2} = mg tan\theta$

$q^2 = mg tan\theta \frac{(2r)^2}{k}$

$= 0.0091 \times 9.8 tan13 \times \frac{(2\times 0.067)^2}{9\times 10^9}$

$q^2 = 4.10\times 10^{-14}$

$q = 2.026 \times 10^{-7} C$

q = ne

$n = \frac{1.6\times 10^{-19}}{2.02\times 10^{-7}}$

$n = 1.266\times 10^{12}$

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Chuge%5Cmathcal%5Ccolorbox%7Bred%7D%7B%5Ccolor%7Bpink%7D%7B%E3%82%AF%E3%82%A8%E3%82%B9%E3

nirvana33 [79]

Answer:

The theory of Relativity state that :<u>Special relativity applies to all physical phenomena in the absence of gravity and General relativity explains the law of gravitation and its relation to other forces of nature. </u>

3 0

3 years ago

Consider blood (density 1025 kg/m3) flowing through an artery with circular cross section that looks like this: Ignore viscosity

Klio2033 [76]

The given question is incomplete. The complete question is attached with an image below.

Explanation:

Mass flow rate through region A will be calculated as follows.

Rate = $\rho \times A \times \mu$

= $\rho \times \pi \times R^{2} \times \mu$

= $1025 \times 3.14 \times (0.5 \times 10^{-2})^{2} \times 30 \times 10^{-2}$

= $24138.75 \times 10^{6} kg/s$

Therefore, we can conclude that the mass flow rate through region A is $24138.75 \times 10^{6} kg/s$ .

8 0

3 years ago