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12345 [234]
4 years ago
11

Anyone know these questions?

Physics
1 answer:
salantis [7]4 years ago
7 0
400m in 32sec: (400/32)>12.5meters per second>
(12.5)(60)(60)(1/1000)=45km per hour
Constant speed would mean that the two forces are equivalent
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A sample of oxygen gas at 25.0°c has its pressure tripled while its volume is halved. What is the final temperature of the gas?
Marat540 [252]

Answer:

447 K

Explanation:

25 C = 25 + 273 = 298 K

Assuming ideal gas, we can apply the ideal gas law

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

T_2 = T_1\frac{P_2}{P_1}\frac{V_2}{V_1}

Since pressure is tripled, then P_2 / P_1 = 3. Volume is halved, then V_2 / V_1 = 0.5

T_2 = 298*3*0.5 = 447 K

4 0
3 years ago
Read 2 more answers
How do you graph motion in physics? How do you graph motion in physics? I've seen problems state that an object is in free fall
Dahasolnce [82]

This is Kinematics and the equations in your book.

A speed time graph would plot the speed of something against the teime it was at a speed.

If it were changing it speed constantly, that would be a straight line if acclerating. Total distrance would be the area under the graph.

5 0
3 years ago
What is a statement that’s summarizes a pattern found in nature
sergey [27]

The answer to your question is,

A scientific law.

-Mabel <3

5 0
3 years ago
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A 10 mH inductor is connected in series with a 10-ohm resistor, a switch and a 6-volt battery.(a) What is the time constant of t
maxonik [38]

Explanation:

It is given that,

Inductance of the inductor, L=10\ mH=10\times 10^{-3}\ H=10^{-2}\ H

Resistance of the resistor, R = 10 ohms

(a) Let \tau is the time constant of the circuit. It is given by :

\tau=\dfrac{L}{R}

\tau=\dfrac{10^{-2}}{10}

\tau=0.001\ s

\tau=1\ ms

(b) The current equation in RL circuit is given by :

I'=I(1-e^{\dfrac{-t}{\tau}})

I' = 0.99 I

0.99=1-e^{\dfrac{-t}{\tau}}

e^{\dfrac{-t}{\tau}}=0.01

e^{\dfrac{-t}{1\ ms}}=0.01

t = 4.6 ms

Hence, this is the required solution.

5 0
3 years ago
A rock is thrown off of a 100 foot cliff with an upward velocity of 45 m/s. As a result its height after t seconds is given by t
oee [108]

Q: A rock is thrown off of a 100 foot cliff with an upward velocity of 45 m/s. As a result its height after t seconds is given by the formula:

h(t)=100+45t−4.9t2

(a) What is its height after 3 seconds?

(b)What is its velocity after 3 seconds?

Answer:

(a) 190.9 m.

(b) 15.6 m/s upward

Explanation:

Given:

h(t) = 100 + 45t - 4.9t²

The height after 3 seconds,

t = 3 s

Substitute the value of t in to the equation above.

h(3) = 100+45(3)-4.9(3)²

h(3) = 100+135-44.1

h(3) = 190.9 m

Therefore the height after 3 seconds = 190.9 m.

(b) Velocity after 3 seconds

The velocity is obtained by differentiating h(t) with respect to time

v = dh(t)/dt

dh(t)/dt = 45-9.8t

v = 45 - 9.8t ......................................... Equation 1

t = 3 s.

Substitute the value of t into the equation above,

v = 45 - 9.8(3)

v = 45- 29.4

v = 15.6 m/s

Thus the velocity after 3 seconds = 15.6 m/s upward

3 0
4 years ago
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