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3 years ago

and both agreed that childhood experiences play an important role in the development of oneself.

2 answers:

8 0

The following answers in the blank could be Sigmund Freud who found the psychoanalysis and Karen Horney who is known to be a psychoanalyst. Both of them has the idea that childhood experiences is necessary and plays the important role in the individual as he or she grows.

emmainna [20.7K]3 years ago

7 0

<h3>Answer;</h3>

A. Sigmund Freud and Alfred Adler

Sigmund Freud and Alfred Adler both agreed that childhood experiences play an important role in the development of oneself.

<h3>Explanation;</h3>

Alfred Adler was Austrian medical doctor and psychotherapist. He turned out to be closely associated with Sigmund Freud who was the founder of psychiatry. Sigmund Freud popularized theories of repression, defense mechanism and the unconscious mind.
Sigmund Freud was a neurologist by heart also from Austria. He firmly believed in one of his greatest contributions to psychology; that is the theory on dream analysis and that human dreams hold many secrets to his subjective nature.
Both Sigmund Freud and Alfred Adler agreed that childhood experiences play an important role in the development of oneself.

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The density of gasoline is 730 kg/m3 at 0°C. Its average coefficient of volume expansion is 9.60 10-4(°C)−1. Assume 1.00 gal of

kipiarov [429]

Answer: 0.4911 kg

Explanation:

We have the following data:

$\rho_{0\°C}= 730 kg/m^{3}$ is the density of gasoline at $0\°C$

$\beta=9.60(10)^{-4} \°C^{-1}$ is the average coefficient of volume expansion

We need to find the extra kilograms of gasoline.

So, firstly we need to transform the volume of gasoline from gallons to $m^{3}$ :

$V=8.50 gal \frac{0.00380 m^{3}}{1 gal}=0.0323 m^{3}$ (1)

Knowing density is given by: $\rho=\frac{m}{V}$ , we can find the mass $m_{1}$ of 8.50 gallons:

$m_{1}=\rho_{0\°C}V$

$m_{1}=(730 kg/m^{3})(0.0323 m^{3})=23.579 kg$ (2)

Now, we have to calculate the factor $f$ by which the volume of gasoline is increased with the temperature, which is given by:

$f=(1+\beta(T_{f}-T_{o}))$ (3)

Where $T_{o}=0\°C$ is the initial temperature and $T_{f}=21.7\°C$ is the final temperature.

$f=(1+9.60(10)^{-4} \°C^{-1}(21.7\°C-0\°C))$ (4)

$f=1.020832$ (5)

With this, we can calculate the density of gasoline at $21.7\°C$ :

$\rho_{21.7\°C}=730 kg/m^{3} f=(730 kg/m^{3})(1.020832)$

$\rho_{21.7\°C}=745.207 kg/m^{3}$ (6)

Now we can calculate the mass of gasoline at this temperature:

$m_{2}=\rho_{21.7\°C}V$ (7)

$m_{2}=(745.207 kg/m^{3})(0.0323 m^{3})$ (8)

$m_{2}=24.070 kg$ (9)

And finally calculate the mass difference $\Delta m$ :

$\Delta m=m_{2}-m_{1}=24.070 kg-23.579 kg$ (10)

$\Delta m=0.4911 kg$ (11) This is the extra mass of gasoline

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