1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nana76 [90]
3 years ago
10

Given that sodium chloride is 39.0% sodium by mass, how many grams of sodium chloride are needed to have 100.mg of Na present? G

iven that sodium chloride is 39.0% sodium by mass, how many grams of sodium chloride are needed to have of Na present? a. 0.256 b. 256 c. 39.0 d. 0.0390 e. none of the above
Chemistry
1 answer:
seraphim [82]3 years ago
8 0

<u>Answer:</u> The mass of sodium chloride solution present is 0.256 grams.

<u>Explanation:</u>

We are given:

39.0 % of sodium in sodium chloride solution

This means that 39.0 grams of sodium is present in 100 grams of sodium chloride solution

Mass of sodium given = 100 mg = 0.1 g     (Conversion factor:  1 g = 1000 mg)

Applying unitary method:

If 39 grams of sodium metal is present in 100 grams of sodium chloride solution

So, if 0.1 grams of sodium metal will be present in = \frac{100}{39}\times 0.1=0.256g of sodium chloride solution.

Hence, the mass of sodium chloride solution present is 0.256 grams.

You might be interested in
the bond formed between the carboxylic acid group of one amino acid and the amino group of the next amino acid is a(n) bond.
Naya [18.7K]

Peptide bonds are amide connections between two amino acids' -carboxyl and -amino groups.

The covalent link created by the dehydration reaction (loss of a water molecule) between the carboxyl group of one amino acid and the amino group on the next is known as a peptide bond. Peptide bonds are created in polypeptides through a condensation reaction between the carboxyl groups of one amino acid and the amino groups of the following amino acid, all while removing water. When the carboxyl group of one molecule combines with the amino group of the other molecule, releasing a molecule of H2O as a result, a peptide bond is created between the two molecules.

Learn more about peptide here-

brainly.com/question/13151387

#SPJ4

4 0
1 year ago
Name two elements that have the same properties as calcium
adoni [48]
Magnesium, strontium and barium are a few of the elements that have the same properties as calcium. elements found in group 2 of the periodic table have similar properties to it.
3 0
3 years ago
Read 2 more answers
Ionization of sodium dichromate​
inessss [21]

Explanation:

this is the answer of your question .

hope it helped you

5 0
3 years ago
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K
Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S

Thus, by combining them, we obtain:

-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}

Which is related to the general line equation:

y=mx+b

Whereas:

y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}

It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Regards!

8 0
3 years ago
A 15.00g solid mixture containing Ca(OH)2, among other non-basic components, was neutralized with 0.2000g of HCl. What was the m
azamat

Answer:

1.373 wt% Ca(OH)₂

Explanation:

Sample mix = 15.0g

Ca(OH)₂(aq) + 2HCl(aq) => CaCl₂(aq) + 2H₂O(l)

moles HCl = 0.2000g / 36 g·mol⁻¹ 0.0056 mol

moles Ca(OH)₂ = 1/2(moles HCl) = 1/2(0.0056 mol) = 0.0028 mol

mass Ca(OH)₂ = 0.0028 mol ( 74 g/mol ) = 0.206 g

mass % Ca(OH)₂ = (0.206/15.0)100% = 1.373 wt%

3 0
3 years ago
Other questions:
  • A coma-like state which may alternate with periods of agitation is likely to be diagnosed as _______ schizophrenia.
    14·2 answers
  • If you dissolve 2.00 g of NiCl2*6h20 into a beaker of water and the final volume is 1.00 liters what will be the molar concentra
    12·1 answer
  • Which is true of an effective scientific model?
    6·2 answers
  • Which ice cream rather have Chocolate- Mint or Cookie IN' Cream?
    14·2 answers
  • Ultraviolet rays from the sun can cause
    7·1 answer
  • When you go down a group, does the tendency for a metal to react (become duller) increase or decrease?
    11·1 answer
  • The mass percent of a solution made by dissolving 59.1 g of kf in 947 g of h2o
    7·1 answer
  • Calculate the number of molecules in 7 moles of oxygen
    13·1 answer
  • Which statement is completely accurate?
    9·1 answer
  • A 10 cm3 piece of aluminum has a higher density than a 5 cm3<br> of aluminum. True or false
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!