Answer:
the vapor density is 1741.6
Explanation:
just divide 560 by 3.11 and you get 1741.6. so the vapour density is 1741.6 hope this helps!
Using physical evidence from multiple different sources, there’s lots of other ways but that’s a starting point
Answer:
1. Hyphothesis 2.Theory 3. law
Explanation:
not sure, but law is observation, theory is based on knowledge things before.
Answer:
a) and d) are false.
Explanation:
a) The second law of thermodynamics states that t<u>he entropy of the universe increases in a spon
taneous process and remains unchanged in an equilibrium process.</u>
For a spontaneous process:
ΔSuniv = ΔSsys + ΔSsurr > 0
For a spontaneous process, the second law says that ΔSuniv must be greater than zero, but it does not place a restriction on either ΔSsys or ΔSsurr. Thus, it is possible for either ΔSsys or ΔSsurr to be negative, as long as the sum of these two quantities is greater than zero.
d) <u>A reaction that does occur under the given set of conditions is called a</u> spontaneous reaction. We observe spontaneous physical and chemical processes every day, including many of the following examples:
• A waterfall runs downhill, but never up, spontaneously.
• A lump of sugar spontaneously dissolves in a cup of coffee, but dissolved sugar does not spontaneously reappear in its original form.
• Heat flows from a hotter object to a colder one, but the reverse never happens spontaneously.
Answer:
27.025 g of H₂O
Explanation:
The Balance chemical equation is
2 H₂ + O₂ = 2 H₂O
Step 1: Calculate Limiting Reagent
Moles of H₂
Mole = 16 g / 2.02 g/mol = 7.937 mol
Moles of O₂
Mole = 24 g / 32.00 g/mol = 0.750 mol
Mole ratio of H₂ : O₂ is 2 : 1. Hence, 7.937 mol of H₂ will need 3.9685 mol of O₂. This means O₂ is limiting reagent.
Step 2: Calculate Moles of H₂O
0.750 mol of O₂ will produce 1.50 mol of H₂O because the mole ratio of O₂ : H₂O is 1 : 2.
Step 3: Calculate mass of H₂O
Mass = 1.50 mol × 18.02 g/mol = 27.025 g of H₂O
