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2 years ago

The perimeter of a rectangular field is 264 yards. If the width of the field is 54 yards, what is its length?

2 answers:

8 0

First, we must multiple the width by two. Then, we subtract the perimeter by that number. Next, we divide the number we have by two.

54 * 2 = 108
264 - 108 = 156
156 / 2 = 78

The perimeter is 78 yards.

SIZIF [17.4K]2 years ago

7 0

P = 2(L + W)
P = 264
W = 54

264 = 2(L + 54)
264 = 2L + 108
264 - 108 = 2L
156 = 2L
156/2 = L
78 <=== Length is 78 yards

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The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
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Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
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Squaring both sides, we get
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In △AOB, we have
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Square rooting both sides
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$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

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