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bija089 [108]
3 years ago
13

A seesaw is an example of a first class lever, true or false?

Physics
1 answer:
kramer3 years ago
6 0
My guess is false because a seesaw goes up and down on both sides, while a lever is when u pick something up and down.

sorry if I'm wrong but I hope it helps :)
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A blank is a statement the summerizes a pattern found in nature
MrMuchimi
What are you asking here?
4 0
3 years ago
A box rests on the floor. If you pull sideways on the box with a 300 N force, but don't move it, what is the magnitude of the fr
Dahasolnce [82]

The magnitude of the frictional force is B) 300 N

Explanation:

For this problem, we just have to consider the forces acting on the box in the horizontal direction.

There are only two forces in this direction:

- The pull applied by the man, of magnitude F=300 N, forward

- The frictional force, F_f, acting backward

So the equation of motion for the box is

F-F_f = ma

where

m is the mass of the box

a is its acceleration

However, the box is at rest, so its acceleration is zero:

a = 0

This means therefore that

F-F_f=0

And so the magnitude of the frictional force is equal to the pulling force:

F_f = F = 300 N

Learn more about friction:

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5 0
3 years ago
An object has 16 N of force being applied to the right, 16 N of force being applied to the left, and 6 N of force being applied
umka2103 [35]

Answer:

the net force on the object is 6 N.

Explanation:

Given;

force applied to the right on the object, F_r = 16 N

force applied to the left of the object, F_l = 16 N

force applied downward on the object, F_d = 6 N

The net horizontal force on the object = F_r - F_l = 16N -16N = 0

The net vertical force on the object = 6 \ N \ downward

The net force on the object is calculated as;

F_{net}^2 = 6^2 + 0\\\\F_{net}^2 = 36\\\\F_{net} = \sqrt{36} \\\\F_{net} = 6 \ N

Therefore, the net force on the object is 6 N.

7 0
3 years ago
Given that the velocity of blood pumping through the aorta is about 30 cm/s, what is the total current of the blood passing thro
TiliK225 [7]

Answer:

94.248 g/sec

Explanation:

For solving the total current of the blood passing first we have to solve the cross sectional area which is given below:

A_1 = \pi R^2\\\\A_1 = \pi (1)^2\\\\A_1 = 3.1416 cm^2

And, the velocity of blood pumping is 30 cm^2

Now apply the following formula to solve the total current

Q = \rho A_1V_1\\\\Q = (1)(3.1416)(30)\\\\

Q =  94.248 g/sec

Basically we applied the above formula So, that the total current could come

3 0
4 years ago
Everything in the world has the same density. True or False?
JulijaS [17]
False
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