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1 year ago

PLEASE ASAP HELP, ILL GIVE WHATEVER POINTS I CAN BUT PLEASE HELP ASAP ASAP

Physics

1 answer:

dalvyx [7]1 year ago

5 0

(1) The ball is in the air for <u>1.4 seconds.</u>

(2) The horizontal velocity of the ball as it rolls off the table is<u> 6.32 m/s.</u>

(3) The vertical velocity of the ball right before it hits the ground is <u>13.72 m/s.</u>

(4) The horizontal velocity of the ball right before it hits the ground is<u> 6.32 m/s.</u>

(5) The initial vertical velocity as soon as the ball comes of the cliff is <u>13.72 m/s.</u>

<h3>What is the time of motion of the ball?</h3>

The time of motion of the ball is calculated by applying the following equation.

t = √(2h/g)

where;

h is the height of the cliff
g is acceleration due to gravity

t = √(2h/g)

t = √(2 x 9.63 / 9.8)

t = 1.4 seconds

The horizontal velocity of the ball is calculated as follows;

v = d/t

where;

d is the horizontal distance travelled by the ball = 8.85 m

v = 8.85 m / 1.4 s

v = 6.32 m/s

The vertical velocity of the ball before it hits the ground is calculated as;

vf = vi + gt

vf = 0 + 9.8 x 1.4

vf = 13.72 m/s

The horizontal velocity of the ball right before it hits the ground is calculated as;

the initial velocity of a projectile = final horizontal velocity

vxf = vxi = 6.32 m/s

The initial vertical velocity as soon as the ball comes off the cliff = final vertical velocity = 13.72 m/s

Learn more about horizontal velocity here: brainly.com/question/24949996

#SPJ1

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