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4 years ago

10

The heat capacity of a sample should be divided by which quantity to find the specific heat capacity? temperature in degrees Cel

sius temperature in kelvins volume in liters mass in grams

2 answers:

lukranit [14]4 years ago

8 0

Answer:

Mass in grams

Explanation:

Rasek [7]4 years ago

5 0

Answer:

Mass on grams

Explanation:

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What is the temperature range on the moon?

jolli1 [7]

When sunlight hits the moon's surface, the temperature can reach 260 degrees Fahrenheit (127 degrees Celsius). When the sun goes down, temperatures can dip to minus 280 F (minus 173 C).

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4 years ago

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You are going to standardize your sodium hydroxide by titrating with potassium hydrogen phthalate. As an example, you dissolve 0

Kay [80]

Answer:

0.13 M

Explanation:

The reaction equation is;

NaOH(aq) + KHC8H4O4(aq) ------> KNaC8H4O4(aq) + H2O(l)

Molar mass of KHP = 204.22 g/mol

Amount of KHP= mass/ molar mass = 0.3365 g/204.22 g/mol = 1.65 × 10^-3 moles

n= CV

Where;

C= concentration

V= volume in dm^3

n= number of moles

C= n/V = 1.65 × 10^-3 moles × 1000/250 = 6.6 × 10^-3 M

If 1 mole of KHP reacts with 1 mole of NaOH

1.65 × 10^-3 moles of KHP will react with 1.65 × 10^-3 moles of NaOH

From

n= CV

We have that only 12.44 ml of NaOH reacted

C= n/V = 1.65 × 10^-3 moles × 1000/12.44

C= 0.13 M

At the equivalence point, the KHP solution turned light pink.

4 0

4 years ago

sodium reacts with chlorine gas to form sodium chloride. if you have 60 L of chlorine gas at STP and 30 g of sodium, how many gr

Stels [109]

Answer:

75.9 grams of salt

Explanation:

The reaction is the following:

2Na(s) + Cl₂(g) → 2NaCl(s) (1)

We have:

m(Na): the mass of sodium = 30 g

V(Cl₂): the volume of the chlorine gas at STP = 60 L

So, to find the mass of NaCl we need to calculate the number of moles of Na and Cl₂.

$n_{Na} = \frac{m}{A_{r}} = \frac{30 g}{22.99 g/mol} = 1.30 moles$

The number of moles of Cl₂ can be found by the Ideal gas law equation:

$PV = n_{Cl_{2}}RT$

Where:

P: is the pressure = 1 atm (at STP)

R: is the gas constant = 0.082 L*atm/(K*mol)

T: is the temperature = 273 K (at STP)

$n_{Cl_{2}} = \frac{PV}{RT} = \frac{1 atm*60 L}{0.082 L*atm/(K*mol)*273 K} = 2.68 moles$

Now we need to find the limiting reactant. From the stoichiometric relation between Na and Cl₂ (equation 1), we have that 2 moles of Na react with 1 mol of Cl₂, so:

$n_{Na} = \frac{2 moles Na}{1 mol Cl_{2}}*2.68 moles Cl_{2} = 5.36 moles$

Since we have 1.30 moles of Na, the limiting reactant is Na.

Finally, we can find the number of moles of NaCl and its mass.

$n_{NaCl} = n_{Na} = 1.30 moles$

$m_{NaCl} = n_{NaCl}*M = 1.30 moles*58.44 g/mol = 75.9 g$

Therefore, would be formed 75.9 grams of salt.

I hope it helps you!

3 0

3 years ago

A 29.0-g sample of water at 290. K is mixed with 51.0 g water at 300. K. Calculate the final temperature of the mixture assuming

zubka84 [21]

Let me conduct my research

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2 years ago

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How is plant photosynthesis and human respiration a example of zero waste world

riadik2000 [5.3K]

Photosynthesis will produce oxygen gas that will be taken up by humans for respiration. Respiration will produce carbon dioxide that will be taken up by plants for photosynthesis. So both waste products will be recycled and reused so therefore an example of zero waste world

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4 years ago

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