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4 years ago

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A cup of gold colored metal bed was measured to have a mask for 25 g. By water displacement, the volume of the bed was calculate

d to be 40.0 mL. Given the following densities, identify the metal. Gold equals 19.3 g/milliliters copper equals 8.86 g/milliliters bronze equals 9.87 g/milliliters

1 answer:

N76 [4]4 years ago

5 0

Answer : The metal is copper.

Explanation :

As we are given that:

Mass of metal = 25 g

Volume of metal = 40.0 mL

Formula used:

$\text{Density of metal}=\frac{\text{Mass of metal}}{\text{Volume of metal}}$

Now putting all the given values in this formula, we get:

$\text{Density of metal}=\frac{25g}{40.0mL}$

$\text{Density of metal}=8.86g/mL$

From this we conclude that the metal is copper whose density is 8.86 g/mL.

Hence, the metal is copper.

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3 years ago

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Answer : The order of process from (1) the least work done by the system to (5) the most work done by the system will be:

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<u>The expression used for work done in reversible isothermal expansion will be,</u>

$w=-nRT\ln (\frac{V_2}{V_1})$

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n = number of moles of gas = 1 mole

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$V_2$ = final volume of gas

First we have to determine the work done for the following process.

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(2) A free isothermal expansion from 1 L to 100 L.

$w=-nRT\ln (\frac{V_2}{V_1})$

$w=-1mole\times 8.314J/moleK\times 298K\times \ln (\frac{100L}{1L})$

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(3) A reversible isothermal expansion from 0.5 L to 4 L.

$w=-nRT\ln (\frac{V_2}{V_1})$

$w=-1mole\times 8.314J/moleK\times 298K\times \ln (\frac{4L}{0.5L})$

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Thus, the order of process from (1) the least work done by the system to (5) the most work done by the system will be:

(1) < (5) < (3) < (4) < (2)

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