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avanturin [10]
3 years ago
6

List the number of significant figures for the following numbers:

Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
3 0

Answer:

a) 2

b) 1

c( 1

d( 4

according to the picture

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Which elements above will form cations? List them below.
cricket20 [7]

Answer:

Halogens always form anions, alkali metals and alkaline earth metals always form cations. Most other metals form cations (e.g. iron, silver, nickel), whilst most other nonmetals typically form anions (e.g. oxygen, carbon, sulfur).

Explanation:

Examples: Sodium (Na+), Iron (Fe2+), Ammonium (NH4

7 0
3 years ago
How many molecules are in 3.0 moles of water
diamong [38]
Hopefully this will help you my friend.

7 0
3 years ago
A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa. If Po2 =
HACTEHA [7]

Answer:

A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa.

<u>The pressure for oxygen is 3 kPa</u>

Explanation:

According to Dalton's Law of Partial Pressure total exerted by the mixture of non-reacting gases is equal to sum of the partial pressure of each gas.

P_{total}=P_{1}+P_{2}+P_{3}

So,

For , a gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure:

P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}

P_{total} = 32.5kPa

P_{O_{2}} = 6.5kPa

P_{N_{2}} = 23.0kPa

Insert the values in :

P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}

32.5 kPa = 6.5 kPa + 23.0 kPa +P_{CO_{2}}

32.5 kPa = 29.5 kPa +P_{CO_{2}}

P_{CO_{2}}= 32.5 - 29.5

P_{CO_{2}}= 3kPa

6 0
3 years ago
How many excess electrons must be added to an isolated spherical conductor 41.0 cmcm in diameter to produce an electric field of
alina1380 [7]

Answer:

3.65 x 10¹⁰ electrons

Explanation:

we'll apply the following equation for electric field of a point charge on a spherical conductor

E = k \frac{q}{r^{2} }

where E is the electric field

k is a constant of the value 8.99 x 10⁹ Nm²/C²

r is the radius of the spherical conductor

q is the total charge in the sphere

Given diameter d =41.0cm, radius r = 20.5cm = 0.205m (convert cm to m)

Electrical field E = 1250 N/C

we are asked to determine how many excess electrons must be added to the surface of the sphere to produce this electric field

E = k \frac{q}{r^{2} }

q = <u>E x r²</u>

        k

q =  <u>1250 N/C x 0.205m</u>²

       8.99 x 10⁹ Nm²/C²

q =   5.84 x 10⁻⁹ C

this is the total charge in the sphere

To determine the number of electrons, we can divide the charge q by the charge on an electron e (1.6 x 10⁻¹⁹C)

n = \frac{q}{e}

n = <u>5.84 x 10⁻⁹ C </u>

       1.6 x 10⁻¹⁹C

n = 3.65 x 10¹⁰ electrons

Therefore, to apply an electric field of magnitude 1250 N/C, the isolated spherical conductor must contain 3.65 x 10¹⁰ electrons

3 0
3 years ago
Given the following balanced equation:
svetlana [45]
So you would just take the coefficient and put it into ratio form

Answers:
1) 4:5
2)4:6
3)6:4
4)6:6
5)6:4
3 0
2 years ago
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