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const2013 [10]
3 years ago
13

What’s the origin of a meteor shower?

Physics
1 answer:
Bogdan [553]3 years ago
6 0

Answer: I hope this helps I read this in a book once

Explanation:

Shower meteors come from the dust released by comets as they travel through our solar system. The dust spreads out along the comet's orbit and forms an elliptical trail of debris that passes around the sun and crosses the orbits of the planets.

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Max hears on the news that a total solar eclipse will be visible from his town in the coming week. Which of the following explai
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I believe that the answer is A but correct me if i’m wrong
7 0
2 years ago
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A/ Can someone help me, how can the third law of motion (Newton) help solve a problem / issue. be specific
mezya [45]

/////////////////////////////////////////////////

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6 0
3 years ago
What is the standard measurement system used by scientists around the world?
sleet_krkn [62]

Answer:

Hey mate....

Explanation:

This is ur answer....

<h3><em>The International System of Units (SI), commonly known as the metric system, is the international standard for measurement.</em></h3>

Hope it helps!

Brainliest pls!

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5 0
2 years ago
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if a car engine does 600,000 J of work over a 500m distance and the mass of the car is 250Kg then what is the final velocity of
drek231 [11]

Given that

Work = 600,000 J ,

distance(S) = 500 m ,

mass (m) = 250 Kg ,

Determine the velocity of car (v) = ?

                 We know that,

                                Work = Force × distance

                               => Force = Work ÷ distance

                                              = 600,000 ÷ 500

                                              = 500 N .

                   Also Force F =  m.a  ; from Newtons II law

                                      500 = 250 × a  

                                             a = 2 m/s.

<em>Final Velocity from the given  formula </em>

                                     V² = u² + 2.a.s

                                         = 0 + 2 × 2 × 500

                                         = \sqrt{2000}

                                    <em>   v = 44.7 m/s</em>

8 0
3 years ago
A force is applied to a block to move it up a 30° incline. The incline is frictionless, the block is initially at rest, F= 65.0
muminat

Answer:

0.96 m, upward

Explanation:

\theta=30^{\circ}

F=65 N

M=5 kg

Initial velocity, u=0

t=0.550 s

Fcos\theta-Mgsin\theta=Ma

Where g=9.8 m/s^2

Substitute the values

65cos30-5\times 9.8sin30=5a

31.8=5a

a=\frac{31.8}{5}=6.36 m/s^2

S=ut+\frac{1}{2}at^2

S=0+\frac{1}{2}(6.36)(0.55)^2=0.96 m

Hence,the block moves upward because displacement is positive.

7 0
3 years ago
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