Gravity is counteracted by centripetal force, due to acceleration, which is the force that pushes you into your seat.
Answer:
1.) 4m
2.) 37 m
3.) 62m
4.) 2.5 s
Explanation:
1.) Given that the
Thinking distance = 1m
Breaking distance = 3m
Stopping distance = breaking distance + thinking distance
Stopping distance = 1 + 3 = 4m
2.) Given that the
Stopping distance = 52 m
Thinking distance = 15m
Breaking distance = 52 - 15 = 37m
3.) The stopping distance = 76m
Thinking distance = 14m
Breaking distance = 76 - 14 = 62m
It take the brakes 62m to slow the car down to a stop.
4.) Given that a lorry travels 28m when stopping from a speed of 4m/s. If its braking distance was 18m, what was the driver’s reaction time?
Thinking = stopping distance - braking distance
Thinking distance = 28 - 18 = 10m
Speed = distance/time
4 = 10/reaction time
Reaction time = 10/4
Reaction time = 2.5 s
5.) Question incomplete
Answer:
5.77×10¹⁰ m
Explanation:
From the question,
Applying
Kepler's third law
P² = d³...................... Equation 1
Where P = Planet's period, d = distance between the center of the planet and the sun.
make d the subject of the formula n equation 1
d = ![\sqrt[3]{P^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7BP%5E%7B2%7D%20%20%7D)
.................. Equation 2
Given: P = 0.24 sidereal.
Substitute the value of P into equation 2
d = ![\sqrt[3]{0.24^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.24%5E%7B2%7D%20%7D)
d = 0.386 Au
d = 0.386×1.496×10¹¹
d = 5.77×10¹⁰ m
Answer:
A
Explanation:
v = change of X / change of T
v = 200/19.3
Answer:
b. The horizontal component of the normal force acts toward the center of the circle.
Explanation:
When a car on a banked turn move with just the right speed so that the frictional force is zero, a component of the normal force -which is always perpendicular to the surface- acts as the centripetal force on the car. This is because the normal force now has a horizontal component, and this component supplies the centripetal force.
