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3 years ago

Please help me. What is 70% of 20?

Mathematics

2 answers:

Gnom [1K]3 years ago

8 0

Answer:

Step-by-step explanation:

20 x 0.7 = 14

uysha [10]3 years ago

8 0

.70 times 20 equals 14

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At the beach 29% of people have red towels and 18% have white towels if the rest have blue ,what percentage of the people at the

Vikki [24]

The percent of people with blue towels would be the remaining percent when you add the red and wight towels together.
a.k.a
53% would have blue towels.

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4 years ago

Suppose a different student reaches in the bag, randomly selects their twenty chips, and estimates that 60% of the students are

djyliett [7]

12 chips if you are trying to find 60% of 20

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4 years ago

Round 0.9874 to the greatest non zero place

Anna71 [15]

0.9874 the greatest non zero place is 9 but the nearest digit is 8 when you round it off to 0.9 the answer becomes 1.0
0.9874~1.0

5 0

3 years ago

A package contains 12 resistors, 3 of which are defective. If 4 are selected, find the probability of getting

s344n2d4d5 [400]

Answer:

Incomplete question, but I gave a primer on the hypergeometric distribution, which is used to solve this question, so just the formula has to be applied to find the desired probabilities.

Step-by-step explanation:

The resistors are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

12 resistors, which means that $N = 12$

3 defective, which means that $k = 3$

4 are selected, which means that $n = 4$

To find an specific probability, that is, of x defectives:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = x) = h(x,12,4,3) = \frac{C_{3,x}*C_{9,4-x}}{C_{12,4}}$

7 0

3 years ago

A set of kitchen containers can be stacked to save space. The height of the stack is given by the expression LaTeX: 1.5c+7.61.5

Nuetrik [128]

Answer:

Part A

The height of the stack made of 8 containers is 19.6 cm

Part B

When the tower is 40.6 cm tall, the number of containers in the set are 22 containers

Part C

(Disagree) The height of a single container is 9.1

Step-by-step explanation:

The question relates to containers, stacked one inside the other such that the height increases by only the wider top edge of the containers

The given expression that gives the height of the stack is presented as follows;

1.5·c + 7.6

Where;

c = The number of containers in the stack

Part A

When there are 8 containers, we have;

h(8) = 1.5 × 8 + 7.6 = 19.6

The height of the stack made of 8 containers, h(8) = 19.6 cm

Part B

When the tower (height of the stack set) is 40.6 cm tall, we have;

h(c) = 1.5·c + 7.6 = 40.6

∴ The number of containers, c = (40.6 - 7.6)/1.5 = 22

When the tower is 40.6 cm tall, the number of containers in the set, c = 22 containers

Part C

Given that the height stack increases only by the thickness of the wider rim of each added container, we have;

The expression for the height of the stack , 1.5·c + 7.6, is the expression for a straight line equation, m·x + c

The thickness of each rim = The slope, of the line, m = The increase in height with number of containers = 1.5

The number of containers (The independent variable, x) = The number of stacked rims = c

The minimum height = The height of a single container = 1.5 × 1 + 7.6 = 9.1

Therefore, the height of a single container = 9.1 not 7.6

4 0

3 years ago