All categories

4 years ago

What is the domain and range of f(x) = -6x^2 - 10x 13?

1 answer:

8 0

The domain of f(x) = -6x^2 - 10x + 13 is all real values.

For the range f(x) = -6x^2 - 10x + 13 written in vertex form is -6(x^2 + 5/3x - 13/6) = -6(x^2 + 5/3x + 25/36 - 13/6 - 25/36) = -6(x + 5/6)^2 - 6(-103/36) = -6(x + 5/6)^2 + 103/6
Range is all real values less than or equal to 103/6

You might be interested in

bought a new car in 2011 for 25000. in 2015, joe was offered a fair price of 12000 for his car but he turned it down. build a li

Mrrafil [7]

Answer:

$y=-3,250t+25,000$

Step-by-step explanation:

we know that

The linear equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope of unit rate of the linear equation

b is the y-intercept or initial value of the linear equation

Let

t ----> the number of years since 2011

y --->the car's value

In this problem the year 2011 represent t=0

the year 2015, represent t=4 years (2015-2011)

we have the ordered pairs

(0,25,000) ----> represent the y-intercept

(4,12,000)

Find the slope m

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{t2-t1}$

substitute the values

$m=\frac{12,000-25,000}{4-0}$

$m=\frac{-13,000}{4}$

$m=-\$3,250\ per\ year$ ---> is negative because is a decreasing function

we have

$b=\$25,000$ ----> value of y when the value of x is equal to zero (initial value)

substitute the given values

$y=-3,250t+25,000$

3 0

3 years ago

Read 2 more answers

What are the answers

Shalnov [3]

Slope formula:
y2-y1
-------
x2-x1
48)
1-3 -2
---- = ----
-2-4 -6

So the slope of MN is 1/3

5 0

3 years ago

Read 2 more answers

Could someone help answer number 1 please

Alekssandra [29.7K]

(4,0) hope this helps!!

7 0

2 years ago

Someone please help.

Alexxandr [17]

Hi there!

$f(x)+f(x+1)=4f(x)$

There are 3 parts to this equation:

f(x)

f(x+1)

4f(x)

We must first determine these three parts separately.

1) f(x)

We're given that $f(x)=3^x$ :

⇒ $f(x)=3^x$ :

2) f(x+1)

Now, we must find f(x+1). To do so, add 1 to x in the original function $f(x)=3^x$ :

⇒ $f(x+1)=3^x^+^1$

3) 4f(x)

To find 4f(x), multiply the original function $f(x)=3^x$ by 4:

$4f(x)=4*3^x$ :

4) Put it all together

Now, plug each of the three parts into the equation $f(x)+f(x+1)=4f(x)$ :

$f(x)+f(x+1)=4f(x)$

$3^x+3^x^+^1=4*3^x\\3^x+3^x*3=4*3^x$

Factor the left side

$3^x*(1+3)=4*3^x$

Divide both sides by 3^x

$1+3=4\\4=4$

Because this equation is true, $f(x)+f(x+1)=4f(x)$ is therefore true.

I hope this helps!

3 0

3 years ago

Find the distance between-10,-13 and 20,-13

Ray Of Light [21]

Answer:

the distance between these 2 would be 30 units

Step-by-step explanation:

Lets ignore the -13 for now because it doesn't have anything to do with the question

Now simply just add 10+ 20 (i took out the negative because it doesn;t make sense)

10+20

=30

plz brainliest :'D

4 0

4 years ago