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3 years ago

15

What is the domain and range of f(x) = -6x^2 - 10x 13?

1 answer:

Naddika [18.5K]3 years ago

8 0

The domain of f(x) = -6x^2 - 10x + 13 is all real values.

For the range f(x) = -6x^2 - 10x + 13 written in vertex form is -6(x^2 + 5/3x - 13/6) = -6(x^2 + 5/3x + 25/36 - 13/6 - 25/36) = -6(x + 5/6)^2 - 6(-103/36) = -6(x + 5/6)^2 + 103/6
Range is all real values less than or equal to 103/6

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6. The pressure exerted on the walls of a container by a gas enclosed within it is directly proportional to

d1i1m1o1n [39]

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Step-by-step explanation:

Given: The pressure exerted on the walls of a container by a gas enclosed within it is directly proportional to the temperature of the gas.

Let 'p' denote the pressure exerted on the walls and 't' denotes temperature of the gas.

Then the equation is given by :-

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Also, the pressure is 6 pounds per square inch when the temperature is 440° F.

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Then, the final equation to calculate pressure becomes :-

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