3 years ago

What is the domain and range of f(x) = -6x^2 - 10x 13?

1 answer:

8 0

The domain of f(x) = -6x^2 - 10x + 13 is all real values.

For the range f(x) = -6x^2 - 10x + 13 written in vertex form is -6(x^2 + 5/3x - 13/6) = -6(x^2 + 5/3x + 25/36 - 13/6 - 25/36) = -6(x + 5/6)^2 - 6(-103/36) = -6(x + 5/6)^2 + 103/6
Range is all real values less than or equal to 103/6

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