(x , y) = (7, - 1)
2x + 3y = 11 → (1)
3x + 3y = 18 → (2)
subtracting (1) from (2) term by term eliminates the y- term
(3x - 2x) + (3y - 3y) = (18 - 11)
x + 0 = 7 ⇒ x = 7
substitute x = 7 into either of the 2 equations and solve for y
(1) → (2 × 7) + 3y = 11
14 + 3y = 11
subtract 14 from both sides
3y = 11 - 14 = - 3
divide both sides by 3
= - 1
solution is (7 , -1)
(x^2 - 3x - 10) * (x - 2) over
(x^2 - 6x + 5) * (x - 5)
(x - 5)(x + 2)(x - 2) over
(x - 5)(x - 1)(x - 5)
(x + 2)(x - 2) is the numerator
(x - 1)(x - 5) is the denominator
excluded values are 1 and 5
7 goes into 357 51 times. First you take 35 and see how many times 7 goes into that and that is 5 than you take 7 and see how many times 7 goes into that and that is 1 time so that you take your to answers and you get 51 as the final answer.
Answer:
x>3
Step-by-step explanation:
Ix<1 is unrelated to the interval as x>3 is.
Answer:
I need degrees and numbers to figure out the answers
