Rubber, because it doesn’t conduct heat and it is a good insulator
Answer:
Hb would be 78.4% saturated.
Explanation:
This problem can be solved by using simple unitary method.
At 100 mm Hg pressure of oxygen, Hb is saturated by 98%
So, at 1 mm Hg pressure of oxygen, Hb is saturated by 
%
Hence, at 80 mm Hg pressure of oxygen, Hb is saturated by 
% or 78.4%
Therefore, at 80 mm Hg pressure of oxygen in the lungs, Hb would be 78.4% saturated.
<span>Answer:
mol Al2O3 x 1 mol Al/ 2 mol Al2O3= .25 mol Al
The balanced equation tells us that it takes 4 moles of Al to produce 2 moles of Al2O3.
0.50 moles Al2O3 x (4 moles Al / 2 moles Al2O3) = 1.0 moles Al
1.0 moles Al x (27.0 g Al / 1 mole Al) = 27.0 g Al</span>
Answer:
66 g of CO₂
Solution:
The Balance Chemical Reaction is as follow,
C₂H₂ + 5/2 O₂ → 2 CO₂ + H₂O
Or,
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O ------- (1)
Step 1: Find out the limiting reagent as;
According to Equation 1,
56.1 g (2 mole) C₂H₂ reacts with = 160 g (5 moles) of O₂
So,
125 g of C₂H₂ will react with = X g of O₂
Solving for X,
X = (125 g × 160 g) ÷ 56.1 g
X = 356.5 g of O₂
It means for total combustion of Ethylene we require 356.5 g of O₂, but we are only provided with 60.0 g of O₂. Therefore, O₂ is the limiting reagent and will control the yield.
Step 2: Calculate Amount of CO₂ produced as;
According to Equation 1,
160 g (5 mole) O₂ produces = 176 g (4 moles) of CO₂
So,
60.0 g of O₂ will produce = X g of CO₂
Solving for X,
X = (60.0 g × 176 g) ÷ 160 g
X = 66 g of CO₂
Answer:
Covalent
Explanation:
Chlorine monofluoride (ClF) is a chemical compound, and the atoms are connected by a single covalent bond.
