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3 years ago

What is the equation of the line that passes through (3,4) and is perpendicular to y=-2x-4

Mathematics

1 answer:

dalvyx [7]3 years ago

7 0

Answer:

y = x/2 + 5/2

Step-by-step explanation:

Plug in and Solve. First find the perpendicular slope to y = -2x -4. It is the negative reciprocal, so m = 1/2.

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4x + 5y = 22<br> 7x - 3y = -32

lana66690 [7]

Answer:

x = -2

y = 6

Step-by-step explanation:

i multiplied the 1st equation by 3 and the 2nd by 5 to get the y-terms to zero out

12x + 15y = 66

+ <u>35x - 15y = -160</u>

47x = -94

x = -94/47

x = -2

substitute -2 for 'x' to solve for 'y':

4(-2) + 5y = 22

-8 + 5y = 22

5y = 30

y = 6

3 0

3 years ago

What is the equation of the graph ?

ZanzabumX [31]

Answer:

what graph

Step-by-step explanation:

4 0

3 years ago

Which of these numbers has the highest value? -22, 0.0099, 0, -1, (-1)

Oliga [24]

.0099 is the only positive number above zero and would have the highest value

5 0

3 years ago

Help me help me 10 points

Shtirlitz [24]

Answer:

arc BC = 84 degrees

Step-by-step explanation:

notice:

need to find n before finding arc BC

(13n -16) + (7n + 12) + 6n = 360

13n + 7n + 6n - 16 + 12 = 360

26n - 4 = 360

26n = 364

n = 364/26 = 14

so arc BC = 6*14 = 84 degrees

3 0

3 years ago

Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.

bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

$cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Substitute $sin(\theta)=\frac{6}{11}$ into the first equation, solve for the cosine and simplify. Then, you obtain:

$cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}$

As $sec\theta$ then $cos\theta$ :

$cos(\theta)=-\frac{\sqrt{85}}{11}$

Now we can find $tan\theta$ :

$tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}$

4 0

3 years ago

Read 2 more answers