1/2-1fgvvvg I am not going to be able to join you for a while I am so happy for you and so much bye
Answer:
![P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{24}](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B24%7D)
Step-by-step explanation:
Given



See attachment for spinner
Required
![P(Cube \ge 5\ and\ Spin[A])](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29)
On a number cube, we have:
---- i.e. 2 outcomes
So, the probability is:



On the spinner, we have:
---- i.e. 1 outcomes
So, the probability is:
![P(Spin[A]) = \frac{n(Spin[A])}{n(Spinner)}](https://tex.z-dn.net/?f=P%28Spin%5BA%5D%29%20%3D%20%5Cfrac%7Bn%28Spin%5BA%5D%29%7D%7Bn%28Spinner%29%7D)
![P(Spin[A]) = \frac{1}{8}](https://tex.z-dn.net/?f=P%28Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B8%7D)
is calculated as thus:
![P(Cube \ge 5\ and\ Spin[A]) = P(Cube \ge 5) * P(Spin[A])](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20P%28Cube%20%5Cge%205%29%20%2A%20P%28Spin%5BA%5D%29)
![P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{3} * \frac{1}{8}](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%2A%20%5Cfrac%7B1%7D%7B8%7D)
![P(Cube \ge 5\ and\ Spin[A]) = \frac{1}{24}](https://tex.z-dn.net/?f=P%28Cube%20%5Cge%205%5C%20and%5C%20Spin%5BA%5D%29%20%3D%20%5Cfrac%7B1%7D%7B24%7D)
To find the percentage, like 50/190, 50÷190 =.2631578947 or simply 26%
Answer:
47/100 or 0.47
Step-by-step explanation:
Answer:
Collage = Bad lol
Step-by-step explanation: