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Mrac [35]
3 years ago
5

Calculate the number of miles of NH4SO4 in 250 ml of a 1.5 M solution

Chemistry
1 answer:
ahrayia [7]3 years ago
3 0
I’m guessing you mean moles. So the big M stands for mol/L. That means first you’d want to convert your mL to L. To do this write your 250mL then make parenthesis for the conversion. 1L=1000mL
250mL(1L/1000mL). Since the mL is on the bottom in the parenthesis we can cancel them out. Now all we do is divide and keep the L.
.250L is what you get. Now we need to figure out how to cancel the L with what we have left. We know M stands for Moles/L so this means in order to get ride of L we need to multiply our new number times the 1.5
.250L X 1.5 moles
_______

1L
This gives us 0.375 moles NH4SO4
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Alex17521 [72]

Answer:

3

Explanation:

It is based on empirical evidence

4 0
3 years ago
Mg + 2HCl → MgCl2 + H2
deff fn [24]

Answer:

Explanation:

This is a limiting reactant problem.

Mg(s)

+

2HCl(aq)

→

MgCl

2

(

aq

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+ H

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(

g

)

Determine Moles of Magnesium

Divide the given mass of magnesium by its molar mass (atomic weight on periodic table in g/mol).

4.86

g Mg

×

1

mol Mg

24.3050

g Mg

=

0.200 mol Mg

Determine Moles of 2M Hydrochloric Acid

Convert

100 cm

3

to

100 mL

and then to

0.1 L

.

1 dm

3

=

1 L

Convert

2.00 mol/dm

3

to

2.00 mol/L

Multiply

0.1

L

times

2.00 mol/L

.

100

cm

3

×

1

mL

1

cm

3

×

1

L

1000

mL

=

0.1 L HCl

2.00 mol/dm

3

=

2.00 mol/L

0.1

L

×

2.00

mol

1

L

=

0.200 mol HCl

Multiply the moles of each reactant times the appropriate mole ratio from the balanced equation. Then multiply times the molar mass of hydrogen gas,

2.01588 g/mol

0.200

mol Mg

×

1

mol H

2

1

mol Mg

×

2.01588

g H

2

1

mol H

2

=

0.403 g H

2

0.200

mol HCl

×

1

mol H

2

2

mol HCl

×

2.01588

g H

2

1

mol H

2

=

0.202 g H

2

The limiting reactant is

HCl

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0.202 g H

2

under the stated conditions.

pls mark as brainliest ans

7 0
2 years ago
Read 2 more answers
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Citrus2011 [14]

Answer: 2948

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.69}{t_{\frac{1}{2}}}=\frac{0.693}{5730}=1.21\times 10^{-4}years^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}years^{-1}

t = age of sample  = ?

a = let initial amount of the reactant  = 100

a - x = amount left after decay process = \frac{70}{100}\times 100=70

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{100}{70}

t=2948years

Thus the fossil is 2948 years old.

5 0
3 years ago
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creativ13 [48]
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5 0
4 years ago
How many core electrons does argon have?
Artemon [7]
10 core electrons are in argon.
4 0
3 years ago
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