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stiks02 [169]
3 years ago
9

Why does the moons gravity affect the earth so much

Physics
2 answers:
Licemer1 [7]3 years ago
7 0
One main reason is, <span>The Moon's gravity pulls on Earth's oceans and distorts them, causing tides</span>
Ronch [10]3 years ago
6 0
The Moon's gravity pulls on Earth's oceans and distorts them, causing tides. The water on the side of Earth closest to the Moon experiences the biggest pull, and bulges outward. The water on the opposite side also bulges, and the two bulges follow the Moon's motion and Earth's rotation.
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A car with a mass of 1600 kg is towing a trailer with a mass of 420 kg. The car
Gekata [30.6K]

Answer:

1.63366

Explanation:

I got this answer from calculator soups physics calculators. I really recommend their website for formulas.  

3 0
3 years ago
Find the focal length of a lens of power-2.0D . What type of lens is this ?
olga_2 [115]

Answer: f = - 0.50 m, negative (diverging) lens

Explanation: D-value (diopter ) means 1/f, unit is 1/m. Thus -2.0D

Means f = ( 1/ -2.0 ) m = -0.50 m

3 0
2 years ago
A disk-shaped platform has a known rotational inertia ID. The platform is mounted on a fixed axle and rotates in a horizontal pl
Zarrin [17]

Answer:

Explanation:

The angular momentum of that same disk-sphere remains unchanged the very same way before and after the impact of the collision when the clay sphere adheres to the disk.

 \mathbf{I_w} = constant.

The overall value of such moment of inertia is now altered when the clay spherical sticks. Due to the inclusion of the clay sphere, the moment of inertia will essentially rise. As a result of this increase, the angular speed w decreases in value.

Recall that:

The Kinetic energy is given by:

\mathbf{K = \dfrac{1}{2} Iw^2} \\ \\\mathbf{K = \dfrac{1}{2} lw*w}

where;

\mathbf{I_w} is constant and w reduces;

As a result, just after the collision, the system's total kinetic energy decreases.

5 0
3 years ago
A 1.2 g pebble is stuck in a tread of a 0.76 m diameter automobile tire, held in place by static friction that can be at most 3.
Maksim231197 [3]

Answer:

v=33.764m/s

Explanation:

Given data

Mass m=1.2 g=0.0012 kg

diameter d=0.76 m

Friction Force F=3.6 N

To find

Velocity v

Solution

From the Centripetal force we know that

F_{c}=\frac{mv^{2} }{r}

Where m is mass

v is velocity

r is radius

Substitute the given values to find velocity v

So

F_{c}=\frac{mv^{2} }{r}\\v^{2}=\frac{F_{c}(r)}{m}\\ v=\sqrt{\frac{F_{c}(r)}{m}}\\ v=\sqrt{\frac{F_{c}(diameter/2)}{m}}\\v=\sqrt{\frac{(3.6N)(0.76/2)m}{(0.0012kg)}}\\v=33.764m/s

4 0
3 years ago
What type(s) of wave(s) transports visible light?
Anuta_ua [19.1K]
The Electromagnetic and Visible Spectra. I believe..
5 0
3 years ago
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