If you kick a soccer ball, you exert a force on it in a certain direction.
The soccer ball will exert an equal amount of force but in the opposite direction, which is on your foot. This is felt as ‘recoil’
That's true.
Netwon's second law states that the resultant of the forces F acting on a body is equal to the product between its mass m and its acceleration a:

This means that if the net force acting on an object is different from zero (term on the left), than the acceleration of the object (term on the right) must be different from zero as well, and therefore the body is accelerating.
In particular, both F and a in the equation are vectors: this means that if the acceleration is positive, F and a have the same direction. In this problem, the acceleration is positive (because the object is speeding up), therefore the force and the acceleration have same direction.
I'm pretty sure it's called, "gravity". or gravy :)
Answer:
α = 5 10⁻³ rad / s²
Explanation:
For this exercise we can use Newton's second law for rotational movement, where the force is electric
τ = I α
Where the torque is
τ = F x r = F r sin θ
Strength is
F = q E
The moment of inertia of a small ball, which we approximate to a point is
I = m r²
We replace
2 (q E) r sin θ = 2m r² α
The number 2 is because the two forces create the same torque
α = q E sin θ
/ m r
Let's reduce the magnitudes to the SI system
m = 1.0g = 1.0 10⁻³ kg
L = 2.0 cm = 2.0 10⁻² m
q = 10 nc = 10 10⁻⁹ C
E = 1.0 10 N / C
r = L / 2
r = 1.0 10⁻² m
Let's calculate
α = 10 10⁻⁹ 1.0 10 sin 30 / 1.0 10⁻³ 1.0 10⁻²
α = 5 10⁻³ rad / s²