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3 years ago

9

Nellie pulls on a 10kg wagon with a constant horizontal force of 30N. If there are no other horizontal gorces what is the wagons

acceleration?

1 answer:

kicyunya [14]3 years ago

3 0

Answer:

$a=3m/s^2$

Explanation:

If we have a net force F acting on a body of mass m it will experiment an acceleration a. Newton's 2nd Law gives us the relation between these quantities: F=ma.

In our case, we want to calculate the acceleration, so we write:

$a=\frac{F}{m}$

With the values we have we get:

$a=\frac{30N}{10Kg}=3m/s^2$

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A 1,200 kg subcompact car accelerates at a rate of 3.0m/s

ludmilkaskok [199]

Missing question (found on internet):
"what is the force of the car?"

Solution:
According to Newton's second law, the force of the car is equal to the product between its mass and its acceleration:
$F=ma$
For the car in the problem,
$m=1200 kg$
$a=3.0 m/s^2$
So the force that accelerates the car is
$F=(1200 kg)(3.0 m/s^2)=3600 N$

6 0

3 years ago

Five equal negative charges are uniformly spaced in a semicircular

balu736 [363]

Answer:

The direction is that of a 3rd quadrant angle

Explanation:

when you have 2 45 angles it equals to 90 then with the 90 we multiply by 2 due to the 2 adjacent angles equating to 180 which swings it to the 3rd quadrant angle

6 0

3 years ago

A 1000 kg mass car moved in a straight, horizontal motion, with a speed of 20m / s, when it was involved in an accident. It was

emmasim [6.3K]

Answer:

average value of the resulting force

Explanation:

The average module value of this resulting force is equivalent to 2.0. 10⁵ N.

The impulse of a force can be calculated by the product of the intensity of the force applied by the time interval in which it is applied -

I = F.Δt

Where,

F = Strength in Newtons

Δt = time interval in seconds

I = Impulse in N.s

The impulse of a force is equivalent to the variation of the amount of movement it causes in the body.

I = ΔQ

The amount of movement is a vector quantity that results from the multiplication of the mass of a body by its speed. Its direction and direction are the same as the velocity vector of the body.

Q = m-V

As the car goes to rest after the application of force, the amount of final movement of the car is equivalent to zero.

I = 0 - mV

F. Δt = - mV

F. 0,1 = - 1000. 20

F = - 20000/0,1

F = 200,000 N

F = 2,0. 10⁵ N

6 0

3 years ago

Josh has a toy car of mass 3 kg tied to a string of length 2 m. He ties the string to a pole and has the toy car drive in a circ

gulaghasi [49]

Part a)

Centripetal acceleration is defined as

$a_c = \frac{v^2}{R}$

now here we know that

$v = 3m/s$

$R = 2 m$

m = 3 kg

now from above formula we have

$a_c = \frac{3^2}{2}$

$a_c = 4.5 m/s^2$

Part b)

Maximum possible tension in the string is given as

$T = 50 N$

now by force equation we have

$F = ma$

$50 = 3 a$

$a = \frac{50}{3} m/s^2$

now again by above formula

$\frac{v^2}{R} = \frac{50}{3}$

$v = \sqrt{\frac{50 \times 2}{3}}$

$v = 5.77 m/s$

5 0

4 years ago

Read 2 more answers

How many moles of mgci2 are there in 326 g of the compound

ddd [48]

<h2>Hello!</h2>

The answer is: There are 3.42 moles of MgCl2 in 326g of the compound.

<h2>Why?</h2>

Assuming that the compound is MgCl2, we can find how many moles of the compound are in 326 g of the same compound, calculating the molar mass of the compound, so:

$Mg=24.305\frac{g}{mol}\\\\Cl=35.45\frac{g}{mol}$

Then,

$MgCl2MolarMass=24.305+(2*35.45)=95.21\frac{g}{mol}$

Therefore, to calculate how many moles are in 326 of the compound, we can use the following equation

$Moles=\frac{mass}{molarmass} =\frac{326g}{95.21\frac{g}{mol}}=3.42molesMgCl2$

Hence,

There are 3.42 moles of MgCl2 in 326g of the compound.

Have a nice day!

6 0

3 years ago