Answer:
114.48g
Explanation:
Step 1:
Data obtained from the question:
Volume (V) = 162 L
Pressure (P) = 1.20 atm
Temperature = 100°C = 100°C+ 273 = 373K
Number of mole (n) of H2O =?
Recall:
Gas constant (R) = 0.082atm.L/Kmol
Step 2:
Determination of the number of mole of H2O i.e steam.
Using the ideal gas equation, the number of mole of H2O can be obtained as follow:
PV = nRT
1.2x 162 = n x 0.082 x 373
Divide both side by 0.082 x 373
n = (1.2x 162) /(0.082 x 373)
n = 6.36 moles
Step 3:
Determination of mass of H2O i.e steam:
This is illustrated below:
Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol
Number of mole H2O = 6.36 moles
Mass of H2O =?
Mass = number of mole x molar Mass
Mass of H2O = 6.36 x 18
Mass of H2O = 114.48g
Therefore, the mass of H2O i.e steam required to fill the drum of crude oil is 114.48g
Waters freezing point in Celsius is 0 and 273.15 Kelvin (or 273 rounded to a whole number.
They have the same number of protons in the nucleus, giving them the same atomic number, but a different number of neutrons giving each elemental isotope a different atomic weight.
Answer:
c) 30
Explanation:
In an atom , the relation between the subatomic particles of the atom are given as follows -
For a neutral atom ,
Atomic number = number of protons = number of electrons ,
Mass number = number of protons + number of neutrons,
Hence , from the given information of the question,
Atomic number of Manganese = 25 ,
mass number of Manganese = 55 ,
Now, to calculate the number of neutrons , the above relation can be used -
Mass number = number of protons + number of neutrons,
Rearranging ,
number of neutrons = Mass number - number of protons
substituting the respective values ,
number of neutrons = 55 - 25 = 30 .
