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aleksandr82 [10.1K]
3 years ago
9

An object was measured by a worker as 14.6 cm long, however, the manufacturer specifications list the length of the object at 14

.4 cm. What is the percent error in the workers measurement
Chemistry
1 answer:
Nitella [24]3 years ago
4 0

Answer:

Explanation:Answer - 0.73%

14.6            .2

         =          

100              x

(Above is proportions I used to get the answer)

x = 0.73% which is the answer.

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What do all atoms and ions of sodium have in common?
nata0808 [166]

They all have the same number of protons (12).

The number of protons (the atomic number) is the same for all atoms and ions of Na.

However, atoms and ions have different numbers of electrons.

An <em>Na atom</em> has 11 electrons, but an <em>Na^(+) ion</em> has only 10 electrons.

7 0
3 years ago
Name the following alkane:
vladimir1956 [14]

The names of the alkanes are 2,2- dimethylbutane, 2,4- dimethylhexane, 2,2,3,3- tetramethylbutane and 4- ethyl, 3,6- dimethyl heptane.

Alkanes are saturated hydrocarbon in the organic chemistry. These are organic compounds that consists of single bonded carbon and hydrogen atoms. The common formula for writing an alkane is given by CₙH₂ₙ₊₂.

Alkanes are further divided into three more types which are:

1. Chain alkanes

2. Cycloalkanes

3. Branched alkanes

Hydrogenation method is used for preparation of alkanes from alkene and alkyne.

The names of the given compounds are:

Part A:

2,2- dimethyl butane

Part B:

2,4- dimethyl hexane

Part C:

2,2,3,3- tetramethyl butane

Part D:

4- ethyl, 3,6- dimethyl heptane

Learn more about alkanes from the link given below.

brainly.com/question/16837399

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4 0
1 year ago
What country was overrun by the Japanese
djverab [1.8K]
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4 0
3 years ago
Read 2 more answers
Determine the equilibrium constant, Keq, at 25°C for the reaction
adelina 88 [10]

Explanation:

The given chemical reaction is:

2Br^- (aq) + I_2(s)  Br_2(l) + 2I^- (aq)

E^ocell=oxidation potential of anode + reduction potential of cathode\\

The relation between Eo cell and Keq is shown below:

deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell

The value of Eo cell is:

Br- undergoes oxidation and I2 undergoes reduction.

Reduction takes place at cathode.

Oxidation takes place at anode.

Hence,

E^ocell= (-1.07+0.53)V\\=-0.54V

F=96485 C/mol

n=2 mol

R=8.314 J.K-1.mol-1

T=298K

Substitute all these values in the above formula:

ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3

Answer:

Keq=6.13x10^33

3 0
3 years ago
If a reaction is completely neutralized, the products would have a pH of<br><br> PLEASE ANSWER!!!!
zysi [14]

Answer:

undefined

Explanation:

It depends on the type of reactants carrying out the reaction.

4 0
3 years ago
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