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3 years ago

8

Awesome Car company sold 20 cars this week.their goal is to sell at least 25% more next week. Write an inequality that represent

s their goal

2 answers:

grigory [225]3 years ago

5 0

Twenty-five percent (25%) of 20 is equal to 5. Therefore, the company is planning or targeting to sell at least 25 cars next week. We let the number of cars be x. The inequality that best represent the scenario above is,
x ≥ 25

kipiarov [429]3 years ago

4 0

Answer:

x ≥ 25

Step-by-step explanation:

The company sold 20 cars this week.

Let the company will sell x cars next week.

Now, it has been given that their goal is to sell at least 25% more next week.

So, first find 25% of 20.

25% of 20

= 0.25 × 20

= 5

Therefore, company will sell at least 20 + 5 = 25 cars next week. At least means ≥

So, mathematically we have

x ≥ 25

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Write an equation of a parabola that passes through (3,-30) and has x-intercepts of -2 and 18. Then find the average rate of cha

Nookie1986 [14]

Answer:

The equation of the parabola is $y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}$ . The average rate of change of the parabola is -4.

Step-by-step explanation:

We must remember that a parabola is represented by a quadratic function, which can be formed by knowing three different points. A quadratic function is standard form is represented by:

$y = a\cdot x^{2}+b\cdot x + c$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$a$ , $b$ , $c$ - Coefficients, dimensionless.

If we know that $(3, -30)$ , $(-2, 0)$ and $(18, 0)$ are part of the parabola, the following linear system of equations is formed:

$9\cdot a +3\cdot b + c = -30$

$4\cdot a -2\cdot b +c = 0$

$324\cdot a +18\cdot b + c = 0$

This system can be solved both by algebraic means (substitution, elimination, equalization, determinant) and by numerical methods. The solution of the linear system is:

$a = \frac{2}{5}$ , $b = -\frac{32}{5}$ , $c = -\frac{72}{5}$ .

The equation of the parabola is $y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}$ .

Now, we calculate the average rate of change ( $r$ ), dimensionless, between $x = -2$ and $x = 8$ by using the formula of secant line slope:

$r = \frac{y(8)-y(-2)}{8-(-2)}$

$r = \frac{y(8)-y(-2)}{10}$

$x = -2$

$y = \frac{2}{5}\cdot (-2)^{2}-\frac{32}{5}\cdot (-2)-\frac{72}{5}$

$y(-2) = 0$

$x = 8$

$y = \frac{2}{5}\cdot (8)^{2}-\frac{32}{5}\cdot (8)-\frac{72}{5}$

$y(8) = -40$

$r = \frac{-40-0}{10}$

$r = -4$

The average rate of change of the parabola is -4.

3 0

2 years ago

What is the rate of change for the function y= 5x+ 25

charle [14.2K]

Answer:

5

Step-by-step explanation:

rate of change = slope = 5

4 0

2 years ago

The standard deviation of the data set is 2.3. Compute the variance to the nearest hundredth. 2,2,2,3,5,5,6,7,8

Arada [10]

The standard deviation is the square root of the variance...so that means the variance is the standard deviation squared.

2.3^2 = 5.29 <===

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3 years ago

Can someone help me out with this ? 8(1 - 8p) + 8p

goldfiish [28.3K]

8(1-8p) + 8p
8 - 64p + 8p
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6 0

2 years ago

Read 2 more answers

Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1 and the given zeros for

timama [110]

The general form of a polynomial is: x² + bx + c = 0. Substituting the roots,

3² + b(3) + c = 0
3b + c = -9 --> eqn 1

(5 + √5)² + (5 +√5)(b) + c = 0
(5+√5)b + c = -30-10√5 --> eqn 2

Solving both equations simultaneously by subtracting eqn 2 from eqn 1,
(-2 - √5)b = 21 + 10√5
b = -8 - √5

Using eqn 1,
3(-8 - √5) + c = -9
-24 - 3√5 + c = -9
c = -9 + 24 + 3√5
c = 15 + 3√5

Hence, the polynomial is: <em>f(x) = x² + (-8 - √5)x + (15 + 3√5)</em>.

7 0

3 years ago