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murzikaleks [220]
3 years ago
15

I need help for my homework cpm 2.3.4 problems 2-86

Mathematics
1 answer:
Vika [28.1K]3 years ago
3 0
69 becuase, Idk I need more points lol
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Sketch the graph of and identify the axis of symmetry
kaheart [24]
The axis of symmetry is found within the set of parenthesis with the x.  If our h value of the vertex is -4, then the axis of symmetry is x = -4.  D is that choice.  Cannot graph it here, but your vertex is sitting at (-4, 4), it's an upside down parabola, and some other points on this graph are (-5, 0), (-3, 0), (-6, -12), (-2, -12).  You could graph it using those points and the vertex without a problem, I'm sure.
6 0
2 years ago
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(4x2 – 6x + 2) + (-5x2 + 6x – 6)
lys-0071 [83]
(4*2-6x+2)+(-5x2+6x-6)
8-6x+2+(-5)*2+6x-6
8-6x+2-10+6x-6
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3 0
3 years ago
Please help and explain.
REY [17]

Answer:

Domain: All real numbers greater than or equal to 1.

Step-by-step explanation:

Answer 1: -14 is not in the domain

Answer 2: 4 is included in the domain

3 0
2 years ago
A car can travel 120km ik 2 hours How long will it take the car to travel 300km
ehidna [41]
It would take the car 5 hours to travel 300km.

Equation used to solve: (120÷2)×6
3 0
3 years ago
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There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
3 years ago
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