Answer:
Correct answer is: D) a₆ = - 11
Step-by-step explanation:
Given:
a₁ = 9 and aₙ = aₙ₋₁ - 4
We know it is
a₆ = a₅ + d also it is given a₆ = a₅ - 4
When we equate the right sides of equality we get:
a₅ + d = a₅ - 4 => d = - 4
We also know it is a₆ = a₁ + 5 d
Now we will find a₆
a₆ = 9 + 5 (-4) = 9 - 20 = - 11
a₆ = - 11
God with you!!!
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Explanation:</h2><h2>
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By using quadratic formula:





So the solutions are:

Answer:
$(0.50+0.75n)
$6.50
Step-by-step explanation:
Please see attached picture for full solution.