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hoa [83]
3 years ago
11

T object]user: which of the following is not correct for an object in projectile motion on earth?

Physics
1 answer:
TiliK225 [7]3 years ago
5 0
The answer is A because if you take into account the friction of the object moving through the air it would cause a slowing of the object in question
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B. Neutrons or Protons Adding or removing protons from the nucleus changes the charge of the nucleus and changes that atom's atomic number. For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium. (Actually, a few neutrons have to be added as well to make the new nucleus stable, but the end result is still helium.)
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How many laws are named after sir issac newton
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Three Laws

Newton's Three Laws of Motion. Sir Isaac Newton: The Universal Law of Gravitation. Sir Isaac Newton and the Unification of Physics & Astronomy.

Explanation:

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Some homes that use baseboard heating use copper tubing. hot water runs through and heats the copper tubing, which in turn heats
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When you heat a certain substance with a difference of temperature \Delta T the heat (energy) you must give to it is
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The orbit of a certain a satellite has a semimajor axis of 4.0 x 107 m and an eccentricity of 0.15. Its perigee (minimum distanc
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100KM and 1kkm

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5 0
4 years ago
A thin ring of radius R is uniformly charged with the total positive charge Q. 1. Find the electric field at distance h right ab
Paha777 [63]

Answer:

E_{net} = \frac{k Q h}{(R^2 + h^2)^{\frac{3}{2}}}

Explanation:

If charge Q is uniformly distributed over the ring then for small element of the ring the charge will be given as

dq = \frac{Q}{2\pi R} dL

now electric field due to this small element on the axis of ring at height "h" is given as

dE = \frac{k dq}{R^2 + h^2}

now since this electric field is radially in the direction of joining the position of charge to the given point

so net field due to ring will be along the axis of ring

so we have

E_{net} = \int dEcos\theta

E_{net} = \int \frac{k dq}{R^2 + h^2} \frac{h}{\sqrt{R^2 + h^2}}

E_{net} = \frac{k Q h}{(R^2 + h^2)^{\frac{3}{2}}}

4 0
3 years ago
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