Answer:
T = 99.51 hour
Explanation:
Mass of Uranus, 
The moon Umbriel orbits Uranus at a distance of 
We need to find Umbriel's orbital period. Let it is T. Using Kepler's third law of motion to find it.
As 1 hour = 3600 s
358244.51 s = 99.51 hour
Hence, Umbriel's orbital period is 99.51 hour.
Heat due to the amount of density difference within a fluid
We know that:
1 mile = 1.61 km
1 gal = 3.8 L
Therefore converting the fuel efficiency rates:
highway = (28.5 km/L) * (1 mile / 1.61 km) * (3.8 L / 1
gal) = 67.27 mile / gal
<span>city = (22.0 km/L) * (1 mile / 1.61 km) * (3.8 L / 1 gal)
= 51.93 mile / gal</span>
Answer:
A pipe has a length of 1.15 m.
a) Determine the frequency of the first harmonic if the pipe is open at each end. The velocity of sound in air is 343 m/s. Answer in units of Hz
b) What is the frequency of the first harmonic if the pipe is closed at one end?
Answer in units of Hz
Explanation:
Answer:
1115560000 J
Explanation:
1/2 * 80,000 * 167^2 m/s = 1115560000 J
