This is going to take a while..
1. 2AgI + Na2S --> Ag2S + 2NaI
2. Na3PO4 + 3HCl --> 3NaCl + N3PO4
3. Ba3N2 + 6H2O --> 3Ba(OH)2 + 2NH3
4. TiCl4 + 2H2O --> TiO2 + 4HCl
5. 3CaCl2 + 2Na3PO4 --> Ca3(PO4)2 + 6NaCl
6. 2NaBr + Cl2 --> 2NaCl + Br2
7. Mg(OH)2 + 2HCl --> MgCl2 + 2H2O
Hopefully that helps.
Answer:
-205.7kj
Explanation:
Now adding reaction 2 and twice of reaction 3 and reverse of reaction 1, we get the enthalpy of the reaction.
The expression for enthalpy for the following reaction will be,
where,
n = number of moles
Now put all the given values in the above expression, we get:
Therefore, the enthalpy of the following reaction is, -205.7kj
12, if the decimal is over five, round up. If it's not, round down. Not sure what you mean by significant figures.
<em>The frequency of the wave with a wavelength of is</em> <u>3.748 × 10 ⁶ /s</u>.
I attached the working and the answer to the question below. I hope I was able to help.
Please note that C = speed of light (2.998 × 10⁸ m/s), ν = frequency and λ= wavelength.
The answer to your question big man would be E