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3 years ago

12

What is the difference between endothermic reactions and exothermic reactions? (Please describe both types of chemical reactions

.)

1 answer:

ryzh [129]3 years ago

3 0

Answer:

Explanation:

Endothermic reactions absorb energy from the surrounding, but exothermic reactions release energy to the surrounding.

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What factors affect the geometry of a molecule?

natali 33 [55]

The factors that affect geometry of a molecule are

> The number of bonding electron pairs around the central atom.

> The number of pairs of non-bonding ("lone pair") electrons around the central atom.

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2 years ago

Which of the following solutions is more concentrated?<br> 0.50M KCl or 5.0% (w/v) KCl

HACTEHA [7]

.50 M KCl because 5% is the same as .05, which makes the .50M more concentrated.

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3 years ago

Which substance most likely has the strongest intermolecular forces?

serious [3.7K]

Answer: -

Acetic acid

Explanation: -

The intermolecular force of attraction depends on the strength or extent of Hydrogen bonding present in a substance.

Benzene and chloroform does not have hydrogen bonding being non polar molecule.

Water has hydrogen bonding being polar.

However acetic acid being most polar has the maximum hydrogen bonding.

Thus acetic acid has the strongest intermolecular forces of attraction.

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3 years ago

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What is conductivity?

r-ruslan [8.4K]

The degree to which a specified material conducts electricity, calculated as the ratio of the card density in the material to the electric field that causes the flow of current. It is the reciprocal of the resistivity.

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3 years ago

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Boron sulfide, B2S3(s), reacts violently with water to form dissolved boric acid (H3BO3) and hydrogen sulfide gas

Gwar [14]

The equation structure for the above mentioned reaction can be written as

$B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow$

<u>Explanation:</u>

Considering the above reaction, When Boron sulfide, reacts with water more violently to form boric acid and hydrogen sulfide gas.

$B_{2} S_{3}+H_{2} O \rightarrow H_{3} B O_{3}+H_{2} S \uparrow$

In order to balance the equation, we can do as follows.There are 2 B - atoms on both sides of the equation, but only 2 H - atoms, and one O - atom on LHS, so we have to balance it by putting 6 in front of water and 2 in front of Boric acid and 3 in front of hydrogen sulphide gas, so that we have 2 B - atoms, 3 - S atoms, 12 H - atoms on both sides of the equation, and it is balanced. Balanced equation is given as,

$B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow$

Thus a Balanced equation of the above mentioned reaction is written.

8 0

3 years ago