I think the answer will be homogeneous mixture
The molar enthalpy of combustion in kj/mol of magnesium is 620 kj/mol, Option D is the correct answer.
<h3>What is enthalpy of Combustion ?</h3>
The energy released when a fuel is oxidized by an oxidizing agent is called enthalpy of Combustion.
It is given that
a 1.0 g sample of magnesium is burned to form MgO. in doing so, 25.5 kj of energy are released.
Molecular weight of Magnesium = 24.35g
24.35 g makes 1 mole of Mg
1g = 1/24.35
For 0.04 moles 25.5 kJ is released
for 1 mole 25.5 *1/.04
= 620 kj/mol
Therefore the molar enthalpy of combustion in kj/mol of magnesium is 620 kj/mol.
To know more about enthalpy of combustion
brainly.com/question/14754029
#SPJ1
Answer:
2.8 m
Explanation:
From the question given above, the following data were obtained:
Number of mole KBr = 0.210 mole
Mass of water = 0.075 kg
Molality of KBr =?
Molality is simply defined as the mole of solute per unit kg of water. Mathematically, it can be expressed as follow:
Molality = mole of solute / Kg of water.
With the above formula, we can obtain the molality of the KBr solution. This can be obtained as follow:
Number of mole KBr = 0.210 mole
Mass of water = 0.075 kg
Molality of KBr =?
Molality = mole of solute / Kg of water.
Molality = 0.210 / 0.075
Molality = 2.8 m
Therefore, the molality of the KBr solution is 2.8 m.
The average atomic weight is calculated by adding up the products of the percentage abundance and atomic weight. In this item, we have the equation,
A = (0.412)(21.016 amu) + (0.5012)(21.942 amu) + (0.0868)(23.974 amu)
Simplifying the operation will give us the answer of 21.74 amu.
<em>Answer: 21.74 amu</em>
The gun type weapon with a uranium core!
