Answer:

Explanation:
Hello,
In this case, as the reaction between sodium hydroxide and sulfuric is:

We can notice a 2:1 molar ratio between the base and the acid, for that reason for the titration at the equivalence point we find:

Which in terms of concentrations and volumes is:

In such a way, solving for the required volume of base we find:

Best regards.
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Ok so rewrite the equation for yourself :).
N2 + 3H2 -> 2NH3 (Always check if it is balanced).
Ok so we have 2kg of hydrogen conver this to grams and then to moles.
2kg -> 2000g
2000g divide by R.M.M of H2
R.M.M
2H - 2 * 1 -> 2
2000/2 - 1000 moles.
Look at the ratio of H2 to 2NH3.
We see that we get 2NH3 for every H2 therefore the ratio is 1:2.
This means that we HAVE 2000 moles of 2NH3.
At stp. we know that 1 moles = 22.4 Litres
We have 2000 moles that means that we produce 44800 litres of NH3 at stp.
2000 * 22.4 - 44800
Hope this helps :).
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