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ryzh [129]
3 years ago
7

Complete the equation determine if there are precipitates write the balanced ionic and net ionic equations. If there is no preci

pitate write the balances molecular and ionic equations:
Sr(NO3)2(aq)+K3PO4(aq)=
NaOH(aq)+Ni(NO3)2=
Chemistry
1 answer:
alukav5142 [94]3 years ago
4 0

You may find bellow the balanced chemical equations.

Explanation:

Molecular equations:

3 Sr(NO₃)₂ (aq) + 2 K₃PO₄ (aq) → Sr₃(PO₄)₂ (s) + 6 KNO₃ (aq)

2 NaOH (aq) + Ni(NO₃)₂ (aq) = Ni(OH)₂ (s) + 2 NaNO₃ (aq)

Ionic equations:

3 Sr²⁺ (aq) + 6 NO₃⁻ (aq) + 6 K⁺ (aq) + 2 PO₄³⁻ (aq) →  Sr₃(PO₄)₂ (s) + 6 K⁺ (aq) + 6 NO₃⁻ (aq)

2 Na⁺ (aq) + 2 OH⁻ (aq) + Ni²⁺ (aq) + 2 NO₃⁻ (aq) = Ni(OH)₂ (s) + 2 Na⁺ (aq) + 2 NO₃⁻ (aq)

To get the net ionic equation we remove the spectator ions:

3 Sr²⁺ (aq) + 2 PO₄³⁻ (aq) →  Sr₃(PO₄)₂ (s)

2 OH⁻ (aq) + Ni²⁺ (aq) = Ni(OH)₂ (s)

Learn more about:

net ionic equations

brainly.com/question/7018960

#learnwithBrainly

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 find the number of moles  of Hydrogen  in ammonium sulfide  (NH4)2S

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Calculate the pH of the following simple solutions:
IceJOKER [234]

Answer :

(1) pH = 1.27

(2) pH = 13.35

(3) The given solution is not a buffer.

Explanation :

<u>(1) 53.1 mM HCl</u>

Concentration of HCl = 53.1mM=53.1\times 10^{-3}M

As HCl is a strong acid. So, it dissociates completely to give hydrogen ion and chloride ion.

So, Concentration of hydrogen ion= 53.1\times 10^{-3}M

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<u>(2) 0.223 M KOH</u>

Concentration of KOH = 0.223 M

As KOH is a strong base. So, it dissociates completely to give hydroxide ion and potassium ion.

So, Concentration of hydroxide ion= 0.223 M

Now we have to calculate the pOH.

pOH=-\log [OH^-]

pOH=-\log (0.223)

pOH=0.65

Now we have to calculate the pH.

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-0.65=13.35

<u>(3) 53.1 mM HCl + 0.223 M KOH</u>

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It is not a buffer because HCl is a strong acid and KOH is a strong base. Both dissociates completely.

As we know that the pH of strong acid and strong base solution is always 7.

So, the given solution is not a buffer.

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3 years ago
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