Question

Complete the equation determine if there are precipitates write the balanced ionic and net ionic equations. If there is no precipitate write the balances molecular and ionic equations:
Sr(NO3)2(aq)+K3PO4(aq)=
NaOH(aq)+Ni(NO3)2=

Answer 1

You may find bellow the balanced chemical equations.

Explanation:

Molecular equations:

3 Sr(NO₃)₂ (aq) + 2 K₃PO₄ (aq) → Sr₃(PO₄)₂ (s) + 6 KNO₃ (aq)

2 NaOH (aq) + Ni(NO₃)₂ (aq) = Ni(OH)₂ (s) + 2 NaNO₃ (aq)

Ionic equations:

3 Sr²⁺ (aq) + 6 NO₃⁻ (aq) + 6 K⁺ (aq) + 2 PO₄³⁻ (aq) →  Sr₃(PO₄)₂ (s) + 6 K⁺ (aq) + 6 NO₃⁻ (aq)

2 Na⁺ (aq) + 2 OH⁻ (aq) + Ni²⁺ (aq) + 2 NO₃⁻ (aq) = Ni(OH)₂ (s) + 2 Na⁺ (aq) + 2 NO₃⁻ (aq)

To get the net ionic equation we remove the spectator ions:

3 Sr²⁺ (aq) + 2 PO₄³⁻ (aq) →  Sr₃(PO₄)₂ (s)

2 OH⁻ (aq) + Ni²⁺ (aq) = Ni(OH)₂ (s)

Learn more about:

net ionic equations

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