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Angelina_Jolie [31]
3 years ago
8

Some lakes, such as the Great Salt Lake, accumulate soluble minerals such as salt. In those lakes, people find it much easier to

float than when they are in fresh water. Why is this the case?
Physics
2 answers:
olga55 [171]3 years ago
5 0
<span>The water with a lot of dissolved minerals and salts is much denser than fresh water. And with a higher density, that means that less water needs to be displaced in order to float. This difference in density can be the difference between barely floating on your back with your nose barely out of the water versus floating comfortably on your back with your entire face out of the water. For instance, fresh water at 25C has a density of 997 kg/m^3, whereas the water in the Great Salt Lake, depending upon the salinity ranges from 1035 kg/m^3 to 1200 kg/m^3. Or in simpler terms it can be about 4% to 20% denser than fresh water and you'll float 4% to 20% higher in the salt water.</span>
erastova [34]3 years ago
4 0

Answer:

B)  The salt water has a greater density than fresh water.

Explanation:

Took the test

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Suppose that the angular separation of two stars is 0.1 arcseconds, and you photograph them with a telescope that has an angular
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Answer: the photograph will likely show only one star.

Explanation:

Since their angular separation is smaller than the telescope's angular resolution, the picture will apparently show only one star rather than two.

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Answer:

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A green block of mass m slides to the right on a frictionless floor and collides elastically with a red block of mass M which is
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Answer:

M is equal to m

Explanation:

In case we say that the green block's mass m is less than red block's mass M, then the green block would have bounced and moved back to the left instead of coming to rest. The other case where if mass of green block's mass m would have been greater than the red block's mass M, the green block would have kept moving to the right instead of coming to rest. After collision, the red block moves to the right because of exchange of velocities. Therefore, m=M since m comes to rest and M moves to the right

In any collision, as it is asumed that no external forces can act during the collision, momentum must be conserved.

So, if we call p₁ to the momentum before collision, and p₂ to momentum after it, taking into account the information above, we can write the following:

p₁ = mv₁ + M.0 = p₂ = m.0 + Mv₂ ⇒ mv₁ = Mv₂

From the question, we also know that it was an elastic collision.

In elastic collision, added to the momentum conservation, it must be conserved the kinetic energy also.

So, if we call k₁ to the kinetic energy prior the collision, and k₂ to the one after it, we can write the following:

k₁ = 1/2 m(v₁)² + 1/2 M.0 = k₂ = 1/2m.0 + 1/2M(v₂)² ⇒ m(v₁)² = M(v₂)²

Mathematically, the only way in which both equations be true, should be with v₁ = v₂,  which is only possible if m=M too.

In this type of collision, it is said that the energy transfers from one mass to the other.

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