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Lady bird [3.3K]
3 years ago
11

Your boss asks you to design a room that can be as soundproof as possible and provides you with three samples of material. The o

nly information on each sample's label is the material's coefficient of absorption. The coefficient of absorption listed on Sample A is 30%, on Sample B is 47%, and on Sample C is 62%. When your boss asks for your choice and the reasoning behind it, what would you tell him?
A. Sample A would be best, because the percentage of the energy in an incident wave that remains in a reflected wave from this material is the smallest.
B. Sample A would be best, because the percentage of the energy in an incident wave that remains in a reflected wave from this material is the largest.
C. Sample C would be best, because the percentage of the energy in an incident wave that remains in a reflected wave from this material is the smallest.
D. Sample C would be best, because the percentage of the energy in an incident wave that remains in a reflected wave from this material is the largest.
Physics
2 answers:
earnstyle [38]3 years ago
4 0

The correct answer is Option C) Sample C would be best, because the percentage of the energy in an incident wave that remains in a reflected wave from this material is the smallest.


As the coefficient of absorption would define the energy present in the reflected wave, the material C has the highest percentage of absorption i.e. 62% and would be best suitable to make a sound proof room.

Alex_Xolod [135]3 years ago
4 0

Answer: Option C: Sample C would be best, because the percentage of the energy in an incident wave that remains in a reflected wave from this material is the smallest.

Explanation:

The absorption coefficient of the samples is given. Sample A has 30%, Sample B has 47% and Sample C has 62%. This means that sample C absorbs the most percentage of energy incident on it. The energy in the reflected wave would be least. Hence, it would be best to use for a room to make it soundproof.


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An IGCSE student thinks it may be possible to identify different rocks (A, B and C) by measuring their
kherson [118]

Answer:

See the answer below

Explanation:

a. The volume in the first measuring cylinder reads 70 cm^3 while that of the second reads 95  cm^3. Hence;

V1 = 70  cm^3

V2 = 95  cm^3

b. <u>An object will always displace its own volume in a liquid</u>. Hence:

Volume V of the rock sample = V2 - V1

   = 95 - 70 = 25  cm^3

c. Mass of A = 102 g

   Volume of A = 25  cm^3

<em>Density = mass/volume</em>

Hence, density of A = 102/25 = 4.08 g/cm^3

8 0
3 years ago
Soap bubble interference Light of 690-nm wavelength interferes constructively when reflected from a soap bubble having refractiv
Nikitich [7]

Answer:

The two possible thicknesses of the soap bubble is 129 nm and 389 nm.

Explanation:

Given that,

Wavelength = 690 nm

Refractive index = 1.33

We need to calculate the two possible thicknesses of the soap bubble

Using formula of thickness

t=\dfrac{(m+\dfrac{1}{2})\lambda}{2n}

For m = 0,

Put the value into the formula

t=\dfrac{\dfrac{690\times10^{-9}}{2}}{2\times1.33}

t=129\times10^{-9}\ m

t=129\ nm

For m=1,

Put the value into the formula

t=\dfrac{\dfrac{3\times690\times10^{-9}}{2}}{2\times1.33}

t=389\times10^{-9}\ m

t=389\ nm

Hence, The two possible thicknesses of the soap bubble is 129 nm and 389 nm.

5 0
2 years ago
Suppose a piano tuner stretches a steel piano wire 7.5 mm. The wire was originally 0.975 mm in diameter, 1.45 m long, and has a
Tasya [4]

The forces a piano tuner applies to stretch the steel piano wire willl be 1.4 × 10¹¹ N.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The application of a force may be used to describe the steel as an elastic element within a certain range of applied force.

Given data;

Young modulus, E=2.10 × 10¹¹ N/m²

Cross-sectional area,A

Final length,\rm L_f = 1.45 m = 1450 \ mm

Initial length,\rm L_i = 7.5 mm

\rm F  = \frac{(L_f-L_i)(E)(A)}{L_1} \\\\ \rm F  = \frac{(1450 - 7.5)(2.0 \times 0^{11})(0.746)}{1450} \\\\ F = 1.4 \times 10^{11} \ N

Hence, the force a piano tuner applies to stretch the steel piano wire willl be 1.4 × 10¹¹ N.

To learn more about the force refer to the link;

brainly.com/question/26115859

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8 0
1 year ago
Compared to the tropical rainforests, the temperate rainforests generally have __________.
Oxana [17]
<span>a. less biomass
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8 0
3 years ago
Asteroid Ida was photographed by the Galileo spacecraft in 1993, and the photograph revealed that the asteroid has a small moon,
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Answer:

The orbital speed of Dactyl is 5.55m/s

Explanation:

The orbital speed can be determined by the combination of the universal law of gravity and Newton's second law:

F = G\frac{M \cdot m}{r^{2}}  (1)

Where G is gravitational constant, M is the mass of the asteroid, m is the mass of the moon and r is the distance between them

In the other hand, Newton's second law can be defined as:

F = ma  (2)

Where m is the mass and a is the acceleration

Then, equation 2 can be replaced in equation 1

m\cdot a  = G\frac{M \cdot m}{r^{2}}  (2)

However, a will be the centripetal acceleration since the moon Dactyl describe a circular motion around the asteroid

a = \frac{v^{2}}{r}  (3)

m\frac{v^{2}}{r} = G\frac{M \cdot m}{r^{2}} (4)

Therefore, v can be isolated from equation 4:

m \cdot v^{2} = G \frac{M \cdot m}{r^{2}}r

m \cdot v^{2} = G \frac{M \cdot m}{r}

v^{2} = G \frac{M \cdot m}{rm}

v^{2} = G \frac{M}{r}

v = \sqrt{\frac{G M}{r}} (5)

Finally, the orbital speed can be found from equation 5:

Notice, that it is necessary to express r in units of meters.

r = 95km \cdot \frac{1000m}{1km} ⇒ 95000m

v = \sqrt{\frac{(6.672x10^{-11}N.m^{2}/kg^{2})(4.4x10^{16}kg)}{95000m}}

v = 5.55m/s

Hence, the orbital speed of Dactyl is 5.55m/s

3 0
2 years ago
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