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2 years ago

6th grade math! Help me please :))

Mathematics

2 answers:

ss7ja [257]2 years ago

8 0

Answer:

It's the third one, down below the first one.

Step-by-step explanation:

It's because it's broken up into three parts, and the mark "M" is at the first one out of three. So it's 1/3

vivado [14]2 years ago

5 0

Answer:

Step-by-step explanation:

after 0, there are 3 lines on the graph, if you count by 1 to 3 on it, it is on 1/3 of it. Hope that this helps you and have a great day :)

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Please if someone could help me that would be greatly appreciated.

mariarad [96]

Answer:

Step-by-step explanation:

5 0

2 years ago

A placebo is a substance that should elicit no positive response in an experimental subject.

adelina 88 [10]

Answer:

A) True

Step-by-step explanation:

In an experiment that has the purpose of testing the efficacy of a procedure or drug, comparison is made against the efficacy of a placebo, a procedure or drug that is intended to have no effect whatever.

Famously, a placebo is often found to be nearly as effective (or even more effective) than the procedure or drug on trial. This effect is known as "the placebo effect."

7 0

2 years ago

A manufacturing company wants to use a sample to estimate the proportion of defective tennis balls that are produced by a machin

Kitty [74]

Answer:

The least number of tennis balls needed for the sample is 1849.

Step-by-step explanation:

The (1 - α) % confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The margin of error for this interval is:

$MOE= z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

Assume that the proportion of all defective tennis balls is p = 0.50.

The information provided is:

MOE = 0.03

Confidence level = 99%

α = 1%

Compute the critical value of z for α = 1% as follows:

$z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$

*Use a z-table.

Compute the sample size required as follows:

$MOE= z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

$n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)} }{MOE}]^{2}$

$=[\frac{2.58\times \sqrt{0.50(1-0.50)} }{0.03}]^{2}\\\\=1849$

Thus, the least number of tennis balls needed for the sample is 1849.

8 0

2 years ago

PLEASE HELP WILL GIVE BRAINLIEST

patriot [66]

Answer:

The answer is (5,-6)

Step-by-step explanation:

it's the only point that's both on the line and and further away from point A

3 0

2 years ago

If A is a 2 × 2 matrix, then A × I = and I × A =

krok68 [10]

Since the multiplication between two matrices is not commutative, then $\vec A\, \times\,\vec I \ne \vec I \,\times \,\vec A$ , regardless of the dimensions of $\vec A$ .

<h3>Is the product of two matrices commutative?</h3>

In linear algebra, we define the product of two matrices as follows:

$\vec C = \vec A \,\times \vec B$ , where $\vec A \in \mathbb{R}_{m\times p}$ , $\vec B \in \mathbb{R}_{p\times n}$ and $\vec C \in \mathbb{R}_{m \times n}$ (1)

Where each element of the matrix is equal to the following dot product:

$c_{ij} = \left[\begin{array}{cccc}a_{i1}&a_{i2}&\ldots&a_{ip}\end{array}\right]\,\bullet\,\left[\begin{array}{ccc}b_{1j}\\b_{2j}\\\vdots\\b_{pj}\end{array}\right]$ , where 1 ≤ i ≤ m and 1 ≤ j ≤ n. (2)

Because of (2), we can infer that the product of two matrices, no matter what dimensions each matrix may have, is not commutative because of the nature and characteristics of the definition itself, which implies operating on a row of the former matrix and a column of the latter matrix.

Such "arbitrariness" means that resulting value for $c_{ij}$ will be different if the order between $\vec A$ and $\vec B$ is changed and even the dimensions of $\vec C$ may be different. Therefore, the proposition is false.

To learn more on matrices: brainly.com/question/9967572

#SPJ1

3 0

1 year ago