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2 years ago

The transfer of heat is through direct contact of particles is called

Physics

1 answer:

mixas84 [53]2 years ago

8 0

The answer would be Conduction!

Hope this helps!!

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A 30 kg child went down a 10 m tall slide. Assuming no energy was lost as friction, what was the child's velocity when he reache

AveGali [126]

14 m/s or 50km/h. See the details in the attached picture.

5 0

2 years ago

Una caja de 5.0kg de masa se acelera desde el reposo a través del piso mediante una fuerza a una tasa de 2.0 /s2 durante 7.0s en

Nady [450]

Responder:

<h2>490 julios </h2>

Explicación:

Se dice que el trabajo se realiza cuando una fuerza aplicada a un objeto hace que el objeto se mueva a través de una distancia. El trabajo realizado por un cuerpo se expresa mediante la fórmula;

Workdone = Fuerza * Distancia

Como Fuerza = masa * aceleración,

Workdone = masa * aceleración * distancia

Masa dada = 5.0kg, aceleración = 2.0m / s² d =?

Para obtener d, usaremos una de las leyes del movimiento,

d = ut + 1 / 2at²

u = 0 (ya que el cuerpo acelera desde el reposo) yt = 7.0s

d = 0 + 1/2 (2) (7) ²

d = 49m

Workdone = 5 * 2 * 49

Workdone = 490 Julios

4 0

2 years ago

If the ball hits olaf and bounces off his chest horizontally at 8.50 m/s in the opposite direction, what is his speed vf after t

Feliz [49]

Answer:

16s/m

Explanation:

3 0

3 years ago

An electron of mass 9.11×10−31 kgkg leaves one end of a TV picture tube with zero initial speed and travels in a straight line t

ki77a [65]

Explanation:

We will use the equations of constant acceleration to find out $a_{x}$ and time t.

As we know that the initial speed is zero. So

(a)

$v_{0x} = 0$

$x - x_{o} = 1.25$ × $10^{-2}$ m

$v_{x} = 3.3$ × $10^{6}$ m/s

$v^{2} _{x} = v^{2} _{x_{o} } + 2a_{x} (x - x_{o} )$

$a_{x} = \frac{v^{2} _{x} - v^{2} _{ox} }{2(x - x_{o}) }$

= $\frac{(3.3 * 10^{6})^{2} - 0 }{2(1.25 * 10^{-2}) }$

= 4.356× $10^{14}$ m/s²

(b)

$v_{x} = v_{ox} + a_{x}t$

$t = v_{x} - vo_{x}/a_{x}$

$t = \frac{3.00 * 10^{6} }{4.356*10^{14} }$ = 6.8870× $10^{-9}$ s

(c)

Σ $F_{x} = ma_{x}$

= (9.11× $10^{-31}$ )(4.356× $10^{14}$ m/s²)

= 3.968× $10^{-16}$ N

6 0

2 years ago

If two 2-kilogram masses are 2 meters apart, what is the gravitational force between them?

Vsevolod [243]

F=G(m1*m2)\D^2

so
G=6.67 × 10^(-11)<span> m</span>3<span> kg</span>-1<span> s</span><span>-2
</span>
= G(2*2)\4
=G

5 0

3 years ago