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mylen [45]
3 years ago
6

A subatomic particle X spontaneously decays into two particles, A and B, each of rest energy 1.40 × 10^2 MeV. The particles fly

off in opposite directions, each with speed 0.827c relative to an inertial reference frame S. What is the total energy of particle A?
Physics
1 answer:
adoni [48]3 years ago
6 0

Answer:

E = 389 MeV

Explanation:

The total energy of particle A, will be equal to the sum of rest mass energy and relative energy of particle A. Therefore,

Total Energy of A = E = Rest Mass Energy + Relative Energy

Using Einstein's Equation: E = mc²

E = m₀c² + mc²

From Einstein's Special Theory of Relativity, we know that:

m = m₀/[√(1-v²/c²)]

Therefore,

E = m₀c² + m₀c²/[√(1-v²/c²)]

E = m₀c²[1 + 1/√(1-v²/c²)]

where,

m₀c² = rest mass energy = 140 MeV

v = relative speed = 0.827 c

Therefore,

E = (140 MeV)[1 + 1/√(1 - (0.827c)²/c²)]

E = (140 MeV)(2.78)

<u>E = 389 MeV</u>

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Answer:

188 A

Explanation:

Parameters given:

Length of cable, L = 0.78 m

Angle, θ = 60º

Magnetic field, B = 5.5 * 10^(-5) T

Force experienced by wire, F = 7 * 10^(-3) N

The force experienced by a current carrying wire of length L, due to a magnetic field B is given as:

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=> I = F/(L * B * sinθ)

I = (7 * 10^(-3)) / (0.78 * 5.5 * 10^(-5) * sin60)

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Answer:

3.982 kg

Explanation:

The latent heat of vaporization = 540 cal/g

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L = 5.4 ×10⁵ × 4.19

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Q = 12 × 750,000

= 9, 000, 000

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the maximum number of kg of water (at 100 degrees Celsius) that could be boiled into steam (at 100 degrees Celsius) is:

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While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. The time taken by the car will be 4 seconds. the correct answer is option(c).

When acceleration is constant, the rate of change in velocity is also constant. In the absence of any acceleration, velocity remains constant. When acceleration is positive, velocity becomes more significant.

Let a denote acceleration, u denote initial velocity, v denote final velocity, and t denote time.

The equation of motion is stated as,

v = u + at

v² = u² + 2as

A car travels across a distance of 60.0 m while accelerating constantly from 12.0 m/s to 18.0 m/s.

Then the time taken by the car will be,

u = 12 m/s

v = 18 m/s

s = 60 m

Put these in the equation v² = u² + 2as.

18² = 12² + 2 x a x 60

a = 1.5

Then the time will be

18 = 12 + 1.5t

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Hence, the time taken is 4 s.

The complete question is:

While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. How much time does it take?

1.00 s

2.50 s

4.00 s

4.50 s

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