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3 years ago

The football player running towards the goal line has

Physics

2 answers:

blagie [28]3 years ago

8 0

the football player has speed

-Dominant- [34]3 years ago

8 0

He has speed, velocity, kinetic energy, hypermotivation, an elevated heart rate, and he typically has THE BALL.

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3 years ago

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A 60 Watt light bulb runs for 120 seconds. How much energy does it use?

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3 years ago

A flea jumps straight up to a maximum height of 0.400 m . what is its initial velocity v0 as it leaves the ground?

timama [110]

For an object`s motion, the Kinematic equation is,

$v^2=v_{0}^2+2ah$

Here, v is the final velocity and h is stands for the height of the object and a is the acceleration of the object.

As according to question,

$v=0m/s,a=g-9.8 m/s^2$ and $h = 0.400 m$

Thus, putting these values in above equation, we get

$0= v_{0}^2 -2gh$

$v_{0} =\sqrt{2 \times 9.8 \times 0.400 }$

$v_{0} = 2.8 m/s$

Therefore, initial velocity is 2.8 m/s

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3 years ago

9. True or false. Training at high altitudes can also increase the amount of

Westkost [7]

False because when the training higher there is less oxygen

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3 years ago

A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 85.0 m/s2

sergey [27]

Answer:

Maximum height attained by the model rocket is 2172.87 m

Explanation:

Given,

Initial speed of the model rocket = u = 0
acceleration of the model rocket = $a\ =\ 85.0 m/s^2$
time during the acceleration = t = 2.30 s

We have to consider the whole motion into two parts

In first part the rocket is moving with an acceleration of a = 85.0 $m/s^2$ for the time t = 2.30 s before the fuel abruptly runs out.

Let $s_1$ be the height attained by the rocket during this time intervel,

$s_1\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s_1\ =\ 0\ +\ 0.5\times 85\times 2.30^2\\\Rightarrow s_1\ =\ 224.825\ m$

And Final velocity at that point be v

$\therefore v\ =\ u\ +\ at\\\Rightarrow v\ =\ 0\ +\ 85.0\times 2.3\\\Rightarrow v\ =\ 195.5\ m/s.$

Now, in second part, after reaching the altitude of 224.825 m the fuel abruptly runs out. Therefore rocket is moving upward under the effect of gravitational acceleration,

Let ' $s_2$ ' be the altitude attained by the rocket to reach at the maximum point after the rocket's fuel runs out,

At that insitant,

initial velocity of the rocket = v = 195.5 m/s.

a = $-g\ =\ -9.81\ m/s^2$
Final velocity of the rocket at the maximum altitude = $v_f\ =\ 0$

From the kinematics,

$v^2\ =\ u^2\ +\ 2as\\\Rightarrow 0\ =\ u^2\ -\ 2gs_2\\\Rightarrow s_2\ =\ \dfrac{u^2}{2g}\\\Rightarrow s_2\ =\ \dfrac{195.5^2}{2\times 9.81}\\\Rightarrow s_2\ =\ 1948.02\ m$

Hence the maximum altitude attained by the rocket from the ground is

$s\ =\ s_1\ +\ s_2\ =\ 224.85\ +\ 1948.02\ =\ 2172.87\ m$

6 0

3 years ago