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Fudgin [204]
3 years ago
8

The football player running towards the goal line has

Physics
2 answers:
blagie [28]3 years ago
8 0

the football player has speed

-Dominant- [34]3 years ago
8 0

He has speed, velocity, kinetic energy, hypermotivation, an elevated heart rate, and he typically has THE BALL.

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The quantity of heat Q that changes the temperature L1Tof a mass mof a substance isgiven by Q = cmt:T, where c is the specific h
White raven [17]

Answer:

a) Q = 80,000 cal

b) Q = 100,000 cal

c) Q = 540,000 cal

d) Q = 720,000 cal

Explanation:

a)1 kg from 0⁰ Ice to 0⁰ water, the heat produced is latent heat of fusion

Q_{l}  = ML_{f} = 1 * 80

Q_{l} = 80 kCal = 80,000 cal

b) 1 kg of O°C ice water to 1 kg of 100°C boiling water

Specific heat capacity, c =  1000cal/kg.C

Q_{c} = mc \delta T\\Q_{c} = 1 * 1000 * (100 - 0)\\Q_{c} =100000 cal

c) 1 kg of 100°C boiling water to 1 kg of 100°C steam

Latent heat of vaporization is needed for this conversion

Q_{v} = ML_{v} \\L_{v} = 540 kCal/kg\\Q_{v} =1* 540 \\Q_{v} = 540 kCal = 540000 cal

d)  1 kg of O°C ice to 1 kg of 100°C steam.

Q = Q_{L} + Q_{c} + Q_{v}

Q = 80,000 + 100,000 + 540,000

Q = 720,000 cal

7 0
4 years ago
A car is traveling at 40 m/s for 20 seconds. How far did it travel in this time?
barxatty [35]
<h3>Answer:</h3>

800 meters

<h3>Explanation;</h3>

<u>We are given;</u>

  • Speed as 40 m/s
  • Time as 20 seconds

We are required to determine the distance traveled

  • Speed refers to the rate of change in distance.
  • It is given by;

Speed = Distance ÷ time

Rearranging the formula;

Distance = speed × time

In this case;

Distance = 40 m/s × 20 sec

              = 800 meters

Thus, the distance traveled by the car is 800 m

7 0
3 years ago
Please help! I'd really appreciate it :-)
Alexxx [7]

Answer:

0.31429 Amps

Explanation:

Using the "Ohm's Law" we can look for the current (amps) with a formula of I = V/R

Given:

Resistance (Ohm) = 350

Volts = 110

Solution:

I = 110v/350r

I = 0.31429 amps

6 0
3 years ago
Determine the energy required to accelerate an electron from (a) 0.500c to 0.900c and (b) 0.900c to 0.990c
Lera25 [3.4K]

Answer:

0.582 MeV

2.45 MeV

Explanation:

E_r=0.511\ MeV=Electron rest energy

(a) 0.500c to 0.900c

W=\left(\frac{1}{\sqrt{1-\frac{v_f^2}{c^2}}}-\frac{1}{\sqrt{1-\frac{v_i^2}{c^2}}}\right)E_r\\\Rightarrow W=\left(\frac{1}{\sqrt{1-0.9^2}}-\frac{1}{\sqrt{1-0.5^2}}\right)0.511\\\Rightarrow W=0.582\ MeV

Energy required is 0.582 MeV

(b) 0.900c to 0.990c

W=\left(\frac{1}{\sqrt{1-\frac{v_f^2}{c^2}}}-\frac{1}{\sqrt{1-\frac{v_i^2}{c^2}}}\right)E_r\\\Rightarrow W=\left(\frac{1}{\sqrt{1-0.99^2}}-\frac{1}{\sqrt{1-0.9^2}}\right)0.511\\\Rightarrow W=2.45\ MeV

Energy required is 2.45 MeV

6 0
3 years ago
An ideal parallel plate capacitor with a cross-sectional area of 0.4 cm2 contains a dielectric with a dielectric constant of 4 a
Mrrafil [7]

Answer: 283.2\times 10^{-9}\ nC

Explanation:

Given

Cross-sectional area A=0.4\ cm^2

Dielectric constant k=4

Dielectric strength E=2\times 10^8\ V/m

Distance between capacitors d=5\ mm

Maximum charge that can be stored before dielectric breakdown is given by

\Rightarrow Q=CV\\\\\Rightarrow Q=\dfrac{k\epsilon_oA}{d}\cdot (Ed)\quad\quad [V=E\cdot d]\\\\\Rightarrow Q=k\epsilon_oAE\\\\\Rightarrow Q=4\times 8.85\times 10^{-12}\times 0.4\times 10^{-4}\times 2\times 10^8\\\\\Rightarrow Q=28.32\times 10^{-8}\\\\\Rightarrow Q=283.2\times 10^{-9}\ nC

4 0
3 years ago
Read 2 more answers
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