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2 years ago

(ii) The Cu2+ ions are attracted to the negative electrode, where they are reduced to produce copper atoms.

1 answer:

5 0

Electrolyte for the electrolysis is copper(II) sulfate
CuSO₄ = Cu²⁺ + SO₄²⁻

the reaction at the negative electrode
(cathode -) Cu²⁺ + 2e⁻ = Cu⁰

and...
(anode +) 2H₂O - 4e⁻ = O₂ + 4H⁺

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Iron has a density of 7.874 g/cm3 what is the mass of a rectangular block of iron with dimensions of 3.000 cm by 4.000cm by 5000

Gemiola [76]

Answer:

mass=? (use the formula given)

Explanation:

density=mass(g)/volume(cm³)

7.874g/cm³=mass x (60000cm³)

mass=?

4 0

2 years ago

6/14and3/7 answer 6/11and9/16answer 5:6=10:12answer

Lubov Fominskaja [6]

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2 years ago

A voltaic cell has one half-cell with a Cu bar in a 1.00 M Cu²⁺ salt, and the other half-cell with a Cd bar in the same volume o

Verizon [17]

The $E^o_{cell}$ of the voltaic cell is 0.743 V. The ΔG°of the given cell is -143.377 kJ and K is 1.35 × 10²⁵

<h3>What is a voltaic cell?</h3>

A voltaic cell often called a galvanic cell, is an electrochemical device that produces electricity through spontaneous redox processes.

It is divided into two distinct half-cells. A half-cell is made up of an electrode (a metal strip, M) dissolved in a solution containing Mn⁺ ions. M can be any metal.

A wire from one electrode to the other connects the two half-cells. Additionally, a salt bridge links the two half-cells.

To solve the question, we need to write the equations of two half-cells

At the anode, oxidation occurs

$Cd(s) \rightarrow Cd^{2+}(aq) + 2e^-$

E° = -0.403 V

At the cathode, reduction occurs

$Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)$

E° = 0.34 V

Overall reaction:

$Cd(s) + Cu^{2+}(aq) \rightarrow Cd^{2+}(aq) + Cu(s)$

We know

$E^o_{cell} = E^o_{cathode} - E^o_{anode}$

= 0.34 -(-0.403) = 0.743 V

Also,

ΔG° = -nF $E^o_{cell}$

Where, n = no of electrons gained or lost

F = Faraday constant

$E^o_{cell}$ = standard potential

ΔG° = -2×96485×0.743 = -143376.71 J = -143.377 kJ

Also,

ΔG° = -RTlnK

-143.377 = -8.314 × 10-3 × 298 × lnK

lnK = 57.87

K = 1.35 × 10²⁵

Hence, The $E^o_{cell}$ of the voltaic cell is 0.743 V. The ΔG°of the given cell is -143.377 kJ and K is 1.35 × 10²⁵

Learn more about Voltaic cell:

brainly.com/question/4430225

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6 0

8 months ago

Is the entropy change favorable or not, when a nonpolar molecule is transferred from water to a nonpolar solvent?

jonny [76]

Answer:

Entropy change is favorable when a nonpolar molecule is transferred from water to a nonpolar solvent.

Explanation:

A nonpolar molecule is not miscible in water (polar solvent). Therefore, when mixed together, each specie will cluster together and solvation will not happen.

However, when you tranfer the nonpolar molecule to a nonpolar solvent, the solvent molecules will interact with the nonpolar molecule. This will increase entropy as the level of disorder will increase with solvation.

8 0

2 years ago

A solution is prepared by dissolving 27.0 g of urea [(NH2)2CO], in 150.0 g of water. Calculate the boiling point of the solution

andrew11 [14]

<u>Answer:</u> The boiling point of solution is 101.56°C

<u>Explanation:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and boiling point of pure solution.

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

Or,

$\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$