The surface area expressed in square feet of a single face of a pile is 1.45 square feet.
<u>Explanation:</u>
The dimensions of the pillar are given as 14 in
14 in
(1 feet = 12 inch)
According to the pillar dimensions mentioned in the problem, the length of the pillar should be 15 inches, height by 14 inches and the width by 14 inches.
There will be two surface areas of the concrete pile, one implies side surface area and the other is end surface area.
For calculating the side surface area,
Area of the side surface = 14 in
15 in
=
= 1.16
1.25
= 1.45 square feet.
(In the given question, only a single face is asked so there is no need to find the surface area of the end face.)
2) Solubility is how much solvent will dissolve in solute.
Answer:
5.96 g/cm^3
Explanation:
Corner atom = 1/8
Atoms in center = 1
Atoms in face of the cube= 1/2
Molar mass of V = 50.94 g/mol <em>(from period table)</em>
1 mole = 6.02x10^23
<em>In BCC unit cell:</em>
(8 x 1/8)+ 1=2 per 1 unit cell
<em>Mass: </em>2(50.94g)/6.02x10^23 = 1.69x10^-22 g/unit cell
305pm=(305x10^-12m÷10^-2m) x (1mL÷1cm^3)
= 2.837 x 10^-23 mL
<em>1pm=10^-12m</em>
<em>1cm=10^-2m</em>
<em>1mL=1cm^3</em>
<em></em>
density=mass/volume
density of V = 1.69x10^-22g÷2.837x10^-23mL
=5.957g/mL
=5.96g/cm^3
A salt derived from a weak base and a strong acid will yield an acid salt