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Pepsi [2]
3 years ago
14

A flask with a volume of 125.0mL contains air with a density of 1.269 g/L. What is the mass of the air contained in the flask?

Chemistry
1 answer:
Aliun [14]3 years ago
4 0
<span>In order to solve this problem you must first make sure all your numbers are in like terms. From the density value you can see that it is grams per liter. The first conversion you must do in convert the 125.0 mL value to Liters which you would do by dividing by 1000 because 1 liter is equal to 1000 mL. 125.0 divided by 1000 is 0.125 Liter. Now you will use the density equation to solve. The density equation is density is equal to mass divided by volume. Plug in your known numbers for density and volume. Then solve for mass. So Density (1.269 g/l is equal to mass divided by volume (.125 Liter) You must rearrange the equation to multiple density by volume which is 1.269 times 0.125 which will give you 0.1586. Because the Liters cancel each other out, the answer's unit will be grams. Your final answer is 0.1586 grams.</span>
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How many atoms are in 4.93 moles hcl?
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1 mole ------------- 6.02x10²³ atoms
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Could someone help me with this?
Varvara68 [4.7K]

Solving part-1 only

#1

KMnO_4

  • Transition metal is Manganese (Mn)

#2

Actually it's the oxidation number of Mn

Let's find how?

\\ \tt\Rrightarrow x+1+4(-2)=0

\\ \tt\Rrightarrow x+1-8=0

\\ \tt\Rrightarrow x-7=0

\\ \tt\Rrightarrow x=+7

  • x is the oxidation number

#3

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#4

\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}

7 0
2 years ago
Which group will have a charge of +2 when ionized?
inysia [295]

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5 0
3 years ago
Read 2 more answers
Using the molarity equation, calculate how many grams of salt you need in order to make 80ml of a 2M solution (MW = 58.44g/mole)
ollegr [7]

Answer:

9.35g

Explanation:

The molarity equation establishes that:

\textrm{molarity}=\frac{\textrm{moles  of solute}}{\textrm{liters of solution}}

So, we have information about molarity (2M) and volume (80 ml=0.08 l), with that, we can find the moles of solute:

\textrm{moles of solute}=\textrm{molarity}*\textrm{liters of solution}

\textrm{moles of solute}= 0.08 \textrm{ l} *2\textrm{ M} = 0.16 \textrm{ mol}

The  mathematical equation that establishes the relationship between molar weight, mass and moles is:

\textrm{molar weight}= \frac{\textrm{mass}}{\textrm{moles}}

\textrm{MW}= \frac{\textrm{m}}{\textrm{n}}

We have MW (58.44g/mole) and n (0.16 mol), and we need to find m (grams of salt needed) to solve the problem:

\textrm{m} = \textrm{MW * n}= 58.44\frac{\textrm{g}}{\textrm{mol}} * 0.16 \textrm{ mol} = 9.35 \textrm{ g}

8 0
3 years ago
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