Lithium Bromide : LiBr.
Molar mass of lithium bromide : 86.845 g/mol.
To find the mass of 2.6 mol of lithium bromide, simply multiply in order to cancel out the moles : 2.6 mol * 86.845 g / 1 mol = 225.8 grams.
Answer:
a) Pb(NO3)2 + 2KI ⇒ PbI2 + 2K(NO3)
ion that form the precipitate = Pb2+ and I-
Spectator ions = NO3. and K+
b) Pb 2+ + 2 I- ⇒ PbI2
Explanation:
Its C increase in temperature
Fe3 because three bigger then two